这是日志（我只包含了匹配的行，实际日志中还有很多其他内容）
/home/steam/pavlovserver/Pavlov/Saved/Logs/Pavlov-backup-2021.07.07-08.51.08.log:[2021.07.06-17.30.30:443][570]PavlovLog: TicketValidation succeed for: 76561198149279501 Saltheili
/home/steam/pavlovserver/Pavlov/Saved/Logs/Pavlov-backup-2021.07.07-08.51.08.log:[2021.07.06-20.56.45:053][555]PavlovLog: TicketValidation succeed for: 76561198041336824 Lumenero
/home/steam/pavlovserver/Pavlov/Saved/Logs/Pavlov-backup-2021.07.07-08.51.08.log:[2021.07.06-22.22.12:299][270]PavlovLog: TicketValidation succeed for: 76561198345598849 GusRemington
/home/steam/pavlovserver/Pavlov/Saved/Logs/Pavlov-backup-2021.07.07-08.51.08.log:[2021.07.07-02.03.19:386][ 55]PavlovLog: TicketValidation succeed for: 76561198302880912 Snitchhy
/home/steam/pavlovserver/Pavlov/Saved/Logs/Pavlov-backup-2021.07.07-08.51.08.log:[2021.07.07-02.40.29:749][786]PavlovLog: TicketValidation succeed for: 76561198291769546 Jupiter
/home/steam/pavlovserver/Pavlov/Saved/Logs/Pavlov-backup-2021.07.07-08.51.08.log:[2021.07.07-03.38.14:208][307]PavlovLog: TicketValidation succeed for: 76561198220506681 Fedora
我正在尝试提取信息并使用它设置变量
id=($(grep 'TicketValidation' ~/pavlovserver/Pavlov/Saved/Logs/* | cut -b 153-170))
date=($(grep 'TicketValidation' ~/pavlovserver/Pavlov/Saved/Logs/* | cut -b 58-67))
name=($(grep 'TicketValidation' ~/pavlovserver/Pavlov/Saved/Logs/* | cut -b 171-270)
这是我想要的格式
$date PlayerName; $name PlayersID; $id
但是我在将它放在 1 行上时遇到了问题，我正试图将它发送到数组，我需要添加[*]某处吗？
如果我运行echo ${id[@]}：
76561198149279501 76561198041336824 76561198345598849 76561198302880912 76561198291769546 76561198220506681
这看起来是正确的，但在名字上我只得到了这个
echo ${name[@]}：
Fedorarygton
如果我运行$ grep **'TicketValidation' ~/pavlovserver/Pavlov/Saved/Logs/* | cut -b 171-270 （来自 $name var 的 grep）
我明白
Saltheili
Lumenero
GusRemington
Snitchhy
Jupiter
Fedora
有想法吗？