正如你所知，当我们编写list=$(ls -l)所有添加的文件时，$list如下所示：
total 0 drwx------ 7 mine-pc staff 238 Dec 22 11:32 Applications drwxr-xr-x@ 6 mine-pc staff 204 Jan 11 11:00 Applications (Parallels) drwx------+ 21 mine-pc staff 714 Jan 9 22:33 Desktop drwx------+ 33 mine-pc staff 1122 Jan 7 23:43 Documents drwx------+ 83 mine-pc staff 2822 Jan 11 00:42 Downloads drwx------@ 71 mine-pc staff 2414 Dec 22 01:10 Library drwx------+ 21 mine-pc staff 714 Jan 10 23:48 Movies drwx------+ 4 mine-pc staff 136 Sep 27 17:48 Music drwxr-xr-x 5 mine-pc staff 170 Jan 4 16:25 Parallels drwx------+ 9 mine-pc staff 306 Dec 29 13:06 Pictures drwxr-xr-x+ 5 mine-pc staff 170 Sep 27 15:41 Public
我怎样才能$list像这样插入它：
drwx------ 7 mine-pc staff 238 Dec 22 11:32 Applications
drwxr-xr-x@ 6 mine-pc staff 204 Jan 11 11:00 Applications (Parallels)
drwx------+ 21 mine-pc staff 714 Jan 9 22:33 Desktop
drwx------+ 33 mine-pc staff 1122 Jan 7 23:43 Documents
drwx------+ 83 mine-pc staff 2822 Jan 11 00:42 Downloads
drwx------@ 71 mine-pc staff 2414 Dec 22 01:10 Library
drwx------+ 21 mine-pc staff 714 Jan 10 23:48 Movies
drwx------+ 4 mine-pc staff 136 Sep 27 17:48 Music
drwxr-xr-x 5 mine-pc staff 170 Jan 4 16:25 Parallels
drwx------+ 9 mine-pc staff 306 Dec 29 13:06 Pictures
drwxr-xr-x+ 5 mine-pc staff 170 Sep 27 15:41 Public
答案1
$list已经是这种格式了。使用引号：
echo "$list"