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如何使用“crunch”生成字符串范围“9811@000000#” - “9811@999999#”？

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如何使用“crunch”生成字符串范围“9811@000000#” - “9811@999999#”？

如何使用生成以下内容crunch？

9811@000000# 
9811@000001#
9811@000002#
9811@000003#
...
9811@999999#

我尝试了这个但是失败了：

crunch 12 12 1234567890 -t '9811@'@@@@@@# -l 9811@@@@@@@#

答案1

从man crunch：

       -t @,%^
              Specifies a pattern, eg: @@god@@@@ where the only the @'s, ,'s,
              %'s, and ^'s will change.
              @ will insert lower case characters
              , will insert upper case characters
              % will insert numbers
              ^ will insert symbols

       -l When you use the -t option this option tells crunch  which  symbols
              should  be treated as literals.  This will allow you to use the
              placeholders as letters in the pattern.  The -l  option  should
              be the same length as the -t option.  See example 15.

       Example 15
       crunch 7 7 -t p@ss,%^ -l a@aaaaa
       crunch  will  now  treat  the  @ symbol as a literal character and not
       replace the character with a uppercase letter.
       this will generate
       p@ssA0!
       p@ssA0@
       p@ssA0#
       p@ssA0$
       <skipped>
       p@ssZ9

因此，您应该将模式改为-t：

  • 决赛@@@@@@​%%%%%%

并以如下模式运行-l：

  • 9811@和@@@@@
  • @@@@@@随便（比如说aaaaaa）
  • #和@

1234567890不再需要，因为您不需要替换字符：

crunch 12 12 -t 9811@%%%%%%# -l @@@@@aaaaaa@

% crunch 12 12 -t 9811@%%%%%%# -l @@@@@aaaaaa@ | head -n 10
Crunch will now generate the following amount of data: 13000000 bytes
12 MB
0 GB
0 TB
0 PB
Crunch will now generate the following number of lines: 1000000 
9811@000000#
9811@000001#
9811@000002#
9811@000003#
9811@000004#
9811@000005#
9811@000006#
9811@000007#
9811@000008#
9811@000009#

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