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我如何告诉系统该服务已启动？

tag-icon • tag-icon systemd python3
我如何告诉系统该服务已启动？

我想将 Python 脚本作为服务运行，脚本启动并运行，但系统显示它处于激活状态，这就是它不断重启的原因

systemd[1]: rpi-rf.service: Failed with result 'timeout'.

如何告诉系统该脚本已启动并正在运行？.service：

    # systemd unit file for the Python Demo Service


[Unit]

# Human readable name of the unit
Description=Python rpi-rf_receiver


[Service]

# Command to execute when the service is started
ExecStart=/usr/bin/python3 /usr/local/lib/rpi-rf/rpi-rf_receive

# Disable Python's buffering of STDOUT and STDERR so that output from the
# service shows up immediately in systemd's logs
Environment=PYTHONUNBUFFERED=1

# Automatically restart the service if it crashes
Restart=on-failure
RestartSec=5

# Our service will notify systemd once it is up and running
Type=notify

# Use a dedicated user to run our service
User=root


[Install]

# Tell systemd to automatically start this service when the system boots
# (assuming the service is enabled)
WantedBy=default.target

答案1

from systemd.daemon import notify, Notification

# Send READY=1
notify(Notification.READY)

答案2

在 systemd 中添加启动项比较复杂，比较麻烦。为了方便使用，有一个工具添加服务提供了一种在 systemd 中快速添加启动项的简单方法。

pip3 install add_service

python -m add_service [shell_file/cmd] [user (default `whoami`)]

例子：

python -m add_service ssh_nat.sh  # by default user is `whoami`
python -m add_service "`which python3` -m http.server 80" root

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