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bash中通过for循环打印同一文件中的多行

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bash中通过for循环打印同一文件中的多行

我想问你如何在同一个文件（例如CONV.inp）中添加一组包含三个值的字符串，一个接一个地？

我想输入 N 行以及各自的值，如下所示：

...

5.834,-54.05,0  
7.728,-10.35,0  
7.796,-14.85,0  
7.871,-4.85,0  
9.397,7.09,0  

...

最后的 0 永远不会改变。我将能够键入每行的两个值，并且只有当我完成时，键入一个随机字母以退出 bash 中的循环。

...

echo -en '\n'
echo "1"
echo -en '\n'
read A
read B
echo "$A,$B,0" >> CONV.inp

echo -en '\n'
echo "2"
echo -en '\n'
read C
read D
echo "$C,$D,0" >> CONV.inp

echo -en '\n'
echo "3"
echo -en '\n'
read E
read F
echo "$E,$F,0" >> CONV.inp 
...

有谁知道如何使用这些功能实现循环？

提前致谢！

答案1

实际上，您想要的是在脚本中使用 do-while 样式的循环，并用于read variable1 variable2同时读取两个值。

#!/bin/bash

# get rid of output_file.txt if it exists, write new file
# This is optional
[ -f output_file.txt  ] && rm output_file.txt

# Read input once, then go into loop and start testing
# User's input
counter=0
read -p "Enter line #$counter or q to quit:" v1 v2
while [ "$v1" != "q"  ]
do
    printf "%s,%s,0\n" "$v1" "$v2" >> output_file.txt
    counter=$(( $counter+1))
    read -p "Enter line vs #$counter or q to quit:" v1 v2
done

测试运行：

$ ./read_double_input.sh                                                                                                 
Enter line #0 or q to quit:5.834 -54.05
Enter line vs #1 or q to quit:7.728 -10.53
Enter line vs #2 or q to quit:7.96 -14.85
Enter line vs #3 or q to quit:q

$ cat output_file.txt
5.834,-54.05,0
7.728,-10.53,0
7.96,-14.85,0

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