请检查并建议我的脚本。我正在尝试获取一个单词(最少 2 个,最多 5 个字符)作为其输入。
用户将提供字符位置,然后脚本会将其从小写更改为大写或大写更改为小写。以下是迄今为止不完整的脚本:
输入:teSt 3
输出: test
#!/bin/bash
clear
while true
do
echo ******TEST*****
read -p 'Enter a word :' word
if [[ ${#word} -le 1 ]] || [[ ${#word} -ge 6 ]]; then
echo "Invalid input (Min of 2 and max of 5)!."
exit 1
fi
echo ${word^^*}
done
答案1
#!/bin/bash
read -p 'Enter a word : ' str id
if [[ ${#str} -le 1 ]] || [[ ${#str} -ge 6 ]]; then
echo "Invalid input (Min of 2 and max of 5)!." && exit 1
idt=$((id-1))
case ${str:idt:1} in
[[:lower:]])
r='\U';
;;
[[:upper:]])
r='\L';
;;
esac
echo $str | sed -r "s/./$r&/$id"
$ ./script.sh
Enter a word : test 1
Test
$ ./script.sh
Enter a word : Test 2
TEst
$ ./script.sh
Enter a word : teST 3
tesT
答案2
您可以使用 ~ 切换大写和小写,
检查这个:
#!/bin/bash
clear
while true
do
echo ******TEST*****
read -p 'Enter a word :' word pos
if [[ ${#word} -le 1 ]] || [[ ${#word} -ge 6 ]]; then
printf "\n\tInvalid input (Min of 2 and max of 5)!.\n\n"
fi
for x in `seq 0 ${#word}`; do
c=${word:$x:1}
if [ "$x" -eq "$(($pos-1))" ]; then
printf "%s" "${c~}"
else
printf "%s" "${c}"
fi
done
printf "\n\n"
done
答案3
该脚本仅切换指定字母的大小写。它不验证输入。
#!/bin/bash
while read -r -p "Enter a word :" word position; do
sed -r "s/([a-z])|([A-Z])/\U\1\L\2/${position}" <<< "$word"
done
测试:
$ ./up_and_low_case.sh
Enter a word :CAT 2
CaT
Enter a word :rabbit 4
rabBit