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捕获返回的错误类型（500、503、402 等）并将其添加到消息中

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捕获返回的错误类型（500、503、402 等）并将其添加到消息中

我如何使该脚本捕获其返回的错误类型（500、503、402 等）并将其添加到消息中？

#!/bin/bash
hostlist=(s-example1.us s-example.2.us)
  for host in "${hostlist[@]}"; do
if nc -w 2 -z $host 80; then
    echo "INFO: ssh on $host responding [Looks Good]"
else
    echo "ERROR: ssh on $host not responding[Ooops something went 
  wrong]"
fi
done

答案1

$?保存最后运行的命令的状态代码。因此，你可以将 else 块修改为：

else
    LAST_STATUS_CODE=$? # save the status code immediately, we don't want to accidentally overwrite it
    echo "ERROR: ssh on $host not responding[Ooops something went wrong]"
    echo "status code: $LAST_STATUS_CODE"
fi

答案2

您似乎混淆了 SSH、HTTP、退出状态和 HTTP 状态代码。如果您需要 HTTP 状态代码，请使用类似 curl 的命令：

$ curl -LI google.com -s | grep 'HTTP/'
HTTP/1.1 302 Found
HTTP/1.1 200 OK

然后：

#!/bin/bash
hostlist=(s-colin.coverhound.us s-joe.coverhound.us)
for host in "${hostlist[@]}"; do
    status=$(curl -LI "$host" -s | grep 'HTTP/')
    if [[ $status == *"200 OK"* ]]; then
        echo "INFO: HTTP on $host responding [Looks Good]"
    else
        echo "ERROR: HTTP on $host not responding [Ooops something went wrong]"
        printf "%s\n" "$status"
    fi
done

因此，hostlist=(google.com/teapot)我会得到：

ERROR: HTTP on $host not responding [Ooops something went wrong]
HTTP/1.1 301 Moved Permanently
HTTP/1.1 418 I'm a Teapot

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