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使用 awk 或 sed 提取部分行

tag-icon • tag-icon shell-script awk sed cut
使用 awk 或 sed 提取部分行 
neterrore=connectionFailure&u=https%3A//data.com/callback%3Fcode%3DY6mOqlD2Cghcub29IlDKB7KHFuGCemVeoNr1lF5r6_c%26state%3DcDi00NM8gO8BImQwp1G0gmdIznygTwXQ&

在此字符串中，我需要在特定字符串之间提取code%3D到 c%26state.

DY6mOqlD2Cghcub29IlDKB7KHFuGCemVeoNr1lF5r6我需要从给定的该行获取输出。

答案1

假设您需要 code%3D 和 c%26state 之间的字符串，这可能会有所帮助

 echo 'neterrore=connectionFailure&u=https%3A//data.com/callback%3Fcode%3DY6mOqlD2Cghcub29IlDKB7KHFuGCemVeoNr1lF5r6_c%26state%3DcDi00NM8gO8BImQwp1G0gmdIznygTwXQ&' | sed 's/.*code%3D\(.*\)c%26state.*/\1/'

答案2

cat /tmp/testfile
"neterrore=connectionFailure&u=https%3A//data.com/callback%3Fcode%3DY6mOqlD2Cghcub29IlDKB7KHFuGCemVeoNr1lF5r6_c%26state%3DcDi00NM8gO8BImQwp1G0gmdIznygTwXQ&"  <-- ignore the ""

string=`awk -F% '{print $4}' /tmp/testfile`
O/P:3DY6mOqlD2Cghcub29IlDKB7KHFuGCemVeoNr1lF5r6_c

echo $string|  sed 's/^.\(.*\).\{2\}$/\1/'
O/P: DY6mOqlD2Cghcub29IlDKB7KHFuGCemVeoNr1lF5r6

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