带菜单的 Bash Shell 脚本

带菜单的 Bash Shell 脚本

我编写了一个 bash shell 脚本(代码如下),为用户提供了 4 个选项。但是我在编写代码时遇到了一点麻烦。现在,当他们选择选项 3 时,显示日期。它会一遍又一遍地循环。我必须关闭终端窗口才能停止它,因为它是一个无限循环。我该如何防止这种情况发生?另外,退出似乎也不起作用。

如果有人能帮助我一点,谢谢。

#!/bin/bashe
 echo -n "Name please? "
 read name
 echo "Menu for $name
    1. Display a long listing of the current directory
    2. Display who is logged on the system
    3. Display the current date and time
    4. Quit "
read input
input1="1"
input2="2"
input3=$(date)
input4=$(exit)
while [ "$input" = "3" ]
do
echo "Current date and time: $input3"
done

while [ "$input" = "4" ]
do
echo "Goodbye $input4"
done

答案1

紧凑版本:

options=(
    "Display a long listing of the current directory"
    "Display who is logged on the system"
    "Display the current date and time"
    "Quit" 
)

PS3="Enter a number (1-${#options[@]}): "

select option in "${options[@]}"; do
    case "$REPLY" in 
        1) ls -l ;;
        2) who ;;
        3) date ;;
        4) break ;;
    esac
done

答案2

我猜这是由于while循环所致;)

的值$input在循环内不会改变。要么read input在循环中插入类似的东西,要么将 更改为while ... do。如果我正确理解了脚本的意图,你现在if ... then不需要这些循环。你需要一个while大的 while循环覆盖从始至终echo "Menu for $name的所有内容。

我的脚本版本如下:

#!/bin/bash
echo -n "Name please? "
read name
input=""
while [ "$input" != "4" ]; do
  echo "Menu for $name
    1. Display a long listing of the current directory
    2. Display who is logged on the system
    3. Display the current date and time
    4. Quit "
  read input
  input1="1"
  input2="2"
  input3=$(date)
  input4=$(exit)
  if [ "$input" = "3" ]; then
    echo "Current date and time: $input3"
  fi

  if [ "$input" = "4" ]; then
    echo "Goodbye $input4"
  fi
done

答案3

案例可以帮助您,尝试一下

 # cat list.sh
 #!/bin/bash
 echo -n "Name please? "
 read name
 echo "Menu for $name"
 echo -e "Enter ( 1 ) to Display a long listing of the current directory \nEnter ( 2 )             to Display who is logged on the system\nEnter ( 3 ) to Display the current date and     time\nEnter ( 4 ) to Quit"
 read en
 case "$en" in
 1)ls -lR;;
 2)who;;
 3)date;;
 4)echo "Good Bye..."
 sleep 0;;
 *)echo "Wrong Option selected" ;;
 esac

输出:

 # ./list.sh
 Name please? Ranjith
 Menu for Ranjith
 Enter ( 1 ) to Display a long listing of the current directory
 Enter ( 2 ) to Display who is logged on the system
 Enter ( 3 ) to Display the current date and time
 Enter ( 4 ) to Quit

如果你输入其他选项,然后菜单显示,然后

 # ./list.sh
 Name please? Ranjith
 Menu for Ranjith
 Enter ( 1 ) to Display a long listing of the current directory
 Enter ( 2 ) to Display who is logged on the system
 Enter ( 3 ) to Display the current date and time
 Enter ( 4 ) to Quit
 5
 Wrong Option selected

...

相关内容