如何从输出文件获取环境变量的访问权限

如何从输出文件获取环境变量的访问权限

我想从输出文件的特定位置获取变量,输入文件格式如下:

log1.txt format:
[v] Output Data
<Value>DIMM_A,4096,1600,Hynix,HMT351S6CFR8C-PB,0942E041,1206,01,Hynix,,</Value>

or log2.txt format:
[v] Output Data
<Value>DIMM_B,4096,1600,Hynix,HMT351S6CFR8C-PB,017E90AE,1205,01,Hynix,,</Value>
<Value>DIMM_A,4096,1600,Hynix,HMT351S6CFR8C-PB,012E908D,1205,01,Hynix,,</Value>

我们希望得到如下格式的输出OUT.TXT文件:

if log1.txt format and then output file format:
SET DIMM1=DIMM_A,4096,1600,Hynix,HMT351S6CFR8C-PB,0942E041,1206,01,Hynix,,

if log2.txt format and then output file format:
SET DIMM2=DIMM_B,4096,1600,Hynix,HMT351S6CFR8C-PB,017E90AE,1205,01,Hynix,,
SET DIMM1=DIMM_A,4096,1600,Hynix,HMT351S6CFR8C-PB,012E908D,1205,01,Hynix,,

你能帮助我吗?谢谢!

答案1

主要问题是我们不知道Value有多少行。因此解决方案有点复杂:

sed -n '/^<Value/{s/^<[^>]*>/=/;s/<[^>]*>$//;p}' log1.txt | sort | cat -n |\
sed 's/^\s\+\([0-9]*\)\s\+=/SET DIMM\1=/'

其中第一个sedgreps 包含 Value 的行并删除<>标签。之后sort将对行进行排序,cat -n枚举它们,最后sed将行号移入DIMM-num-

这样awk就非常接近sed解决方案了:

awk -F'>' '/^<Value/{gsub ("<.*", "", $2);print $2}' log1.txt | sort |\
awk '{print "SET DIMM"NR"="$0}'

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