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我想要在unix中对日期2018-03-28到2018-04-02进行while循环

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我想要在unix中对日期2018-03-28到2018-04-02进行while循环

我想要 UNIX 中日期 2018-03-28 到 2018-04-02 的 while 循环语法

答案1

根据评论中用户的意愿进行编辑以使用YYYYMMDD输出格式而不是格式，并添加也取自评论的开始日期和结束日期变量。YYYY-MM-DD

假设 GNU date：

startdate='2018-03-28'
enddate='2018-04-02'

enddate=$( date -d "$enddate" +%Y%m%d )  # rewrite in YYYYMMDD format
i=0
while [ "$thedate" != "$enddate" ]; do
    thedate=$( date -d "$startdate + $i days" +%Y%m%d ) # get $i days forward
    printf 'The date is "%s"\n' "$thedate"
    i=$(( i + 1 ))
done

或者：

startdate='2018-03-28'
enddate='2018-04-02'

enddate=$( date -d "$enddate + 1 day" +%Y%m%d )   # rewrite in YYYYMMDD format
                                                  #  and take last iteration into account
thedate=$( date -d "$startdate" +%Y%m%d )
while [ "$thedate" != "$enddate" ]; do
    printf 'The date is "%s"\n' "$thedate"
    thedate=$( date -d "$thedate + 1 days" +%Y%m%d ) # increment by one day
done

输出：

The date is "20180328"
The date is "20180329"
The date is "20180330"
The date is "20180331"
The date is "20180401"
The date is "20180402"

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