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为什么 Interix mkdir 不遵守 -p 参数？

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为什么 Interix mkdir 不遵守 -p 参数？

我在 Windows 上使用 Interix 来实现 Unix 兼容性，但发现它的-p行为mkdir不符合我的预期：

> which mkdir
C:\SFU\bin\mkdir

> mkdir -p c:\Program Files\
A subdirectory or file -p already exists.
Error occurred while processing: -p.

SUA 手册页中 mkdir 的部分内容如下：

NAME
     mkdir - make directories

SYNOPSIS
     mkdir [-p] [-m mode] directory_name [...]

DESCRIPTION
     The mkdir utility creates the directories named as operands, in the order
     specified, using mode rwxrwxrwx (0777) as modified by the current
     umask(2).

     -p      Create intermediate directories as required.  If this option is
             not specified, the full path prefix of each operand must already
             exist.  Intermediate directories are created with permission bits
             of rwxrwxrwx (0777) as modified by the current umask, plus write
             and search permission for the owner.  Do not consider it an error
             if the argument directory already exists.

为什么我传递了 却收到有关现有目录的错误-p？似乎-p未被识别为标志，而是创建了一个名为 的目录-p。您如何传递-p参数？

答案1

mkdir选取的是窗口，而不是 Interix 窗口。我通过提供 Interixmkdir位置的完整路径来避免此问题。即使which mkdir提供了 Interix 路径，这也是必要的。

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