将制表符替换为空格

将制表符替换为空格

输入 json:

[
  {
    "name": "cust1",
    "grp": [
      {
        "id": "46",
        "name": "BA2"
      },
      {
        "id": "36",
        "name": "GA1"
      },
      {
        "id": "47",
        "name": "NA1"
      },
      {
        "id": "37",
        "name": "TR3"
      },
      {
        "id": "38",
        "name": "TS1"
      }
    ]
  }
]

如何在 @tsv 输出上获取用空格分隔的 .grp[] 名称?

$ jq -r '.[]|[.name, (.grp//[{"name":"-"}]|.[]|" ",.name)]|@tsv' test_inp
cust1           BA2             GA1             NA1             TR3             TS1

上述示例的预期输出:

cust[TAB]BA2[SPACE]GA1[SPACE]NA1[SPACE]TR3[SPACE]TS1

答案1

jq方法:

jq -r '.[] | [.name, (.grp | map(.name) | join(" "))] | @tsv' input.json

输出:

cust1   BA2 GA1 NA1 TR3 TS1

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