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如何通过cmd获取网络中电脑的IPV4地址？

tag-icon • tag-icon windows networking command-line
如何通过cmd获取网络中电脑的IPV4地址？

我一直使用tracert和ping命令来获取我的计算机的 IPV4 地址。现在我似乎无法这样做：

C:\>tracert win7x64

Tracing route to WIN7X64 [fe80::f44f:fb88:3026:4ecc%53] over a maximum of 30 hops:

  1    <1 ms    <1 ms    <1 ms  WIN7X64 [fe80::f44f:fb88:3026:4ecc]

Trace complete.

C:\>ping win7x64

Pinging WIN7X64 [fe80::f44f:fb88:3026:4ecc%53] with 32 bytes of data:
Reply from fe80::f44f:fb88:3026:4ecc%53: time<1ms
Reply from fe80::f44f:fb88:3026:4ecc%53: time<1ms
Reply from fe80::f44f:fb88:3026:4ecc%53: time<1ms
Reply from fe80::f44f:fb88:3026:4ecc%53: time<1ms

Ping statistics for fe80::f44f:fb88:3026:4ecc%53:
    Packets: Sent = 4, Received = 4, Lost = 0 (0% loss),
Approximate round trip times in milli-seconds:
    Minimum = 0ms, Maximum = 0ms, Average = 0ms

是否有一个 Windows 命令可以仅通过了解计算机名称来获取网络中某台计算机的 IPV4 地址？谢谢！

答案1

您可以执行此操作ping -4 win7x64来获取 IPv4 IP 地址。

对于跟踪路由，您可以使用tracert -4 win7x64。

从ping /?：

Usage: ping [-t] [-a] [-n count] [-l size] [-f] [-i TTL] [-v TOS]
            [-r count] [-s count] [[-j host-list] | [-k host-list]]
            [-w timeout] [-R] [-S srcaddr] [-4] [-6] target_name
Options:
    -4             Force using IPv4.

来自tracert /?：

Usage: tracert [-d] [-h maximum_hops] [-j host-list] [-w timeout]
               [-R] [-S srcaddr] [-4] [-6] target_name
Options:
    -4                 Force using IPv4.

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