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使用jq进行Json转换

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使用jq进行Json转换

我想将 json 转换为新行分隔的 json。我尝试在 bash 中使用 jq 多次执行此操作，但我无法接近最终输出。

输入：

{
    "windows124": {
        "updated": "2015-01-14",
        "attribution": [],
        "description": "",
        "notes": [],
        "alt_names": [],
        "sources": [],
        "urls": ["google.com", "google.co.uk"],
        "common_name": "test",
        "uuid": "7259334c-3218-4259-aaab-896d87507f4f"
    },
    "linux124": {
        "updated": "",
        "attribution": ["Naifdddkoscn"],
        "description": "",
        "notes": [],
        "alt_names": [],
        "sources": [],
        "urls": ["https://example.com/1.pdf", "https://example.com/1.pdf", "https://example.com/1.pdf"],
        "common_name": "121212",
        "uuid": "009db412-762d-4256-8df9-eb213be01ffd"
    },
    "wikipedia123": {
        "updated": "2018-07-31",
        "attribution": [],
        "description": "",
        "notes": [],
        "alt_names": [],
        "sources": [],
        "urls": ["https://example.com/1.pdf"],
        "common_name": "test343",
        "uuid": "4d8da0af-cfd7-4990-b211-af0e990vfda0"
    }
}

想要的输出：

{"uuid": "7259334c-3218-4259-aaab-896d87507f4f","family": "windows124","updated": "2015-01-14","attribution": [],"description": "","notes": [],"alt_names": [],"sources": [],"urls": ["google.com", "google.co.uk"],"common_name": "test"}
{"uuid": "009db412-762d-4256-8df9-eb213be01ffd","family": "linux124", "updated": "","attribution": ["Naifdddkoscn"],"description": "","notes": [],"alt_names": [],"sources": [],"urls": ["https://example.com/1.pdf", "https://example.com/1.pdf", "https://example.com/1.pdf"],"common_name": "121212"}
{"uuid": "4d8da0af-cfd7-4990-b211-af0e990vfda0","family": "wikipedia123", "updated": "2018-07-31","attribution": [],"description": "","notes": [],"alt_names": [],"sources": [],"urls": ["https://example.com/1.pdf"],"common_name": "test343"}

到目前为止我所拥有的是：cat deserialize.json | jq -c '.|to_entries[]'

{"key":"windows124","value":{"updated":"2015-01-14","attribution":[],"description":"","notes":[],"alt_names":[],"sources":[],"urls":["google.com","google.co.uk"],"common_name":"test","uuid":"7259334c-3218-4259-aaab-896d87507f4f"}}
{"key":"linux124","value":{"updated":"","attribution":["Naifdddkoscn"],"description":"","notes":[],"alt_names":[],"sources":[],"urls":["https://example.com/1.pdf","https://example.com/1.pdf","https://example.com/1.pdf"],"common_name":"121212","uuid":"009db412-762d-4256-8df9-eb213be01ffd"}}
{"key":"wikipedia123","value":{"updated":"2018-07-31","attribution":[],"description":"","notes":[],"alt_names":[],"sources":[],"urls":["https://example.com/1.pdf"],"common_name":"test343","uuid":"4d8da0af-cfd7-4990-b211-af0e990vfda0"}}

答案1

您可以使用此 jq 过滤器：

<file jq 'to_entries|map(.value + {family:(.key)})[]'

正如您所发现的，该to_entries函数允许获取键名称以添加属性family。

所以过滤器只创建这个对象并将其添加到函数给定family的内容中。valueto_entries

该map函数对数组的所有元素执行添加操作value。

最后[]去掉了外部数组。

请注意，输出的顺序与您发布的方式不同，但内容是相同的。如果您希望对键进行排序，请使用选项-S。

答案2

jq -c 'with_entries(.value.family = .key)[]' file.json

或者，

jq -c 'with_entries(.value += { family: .key })[]' file.json

这会将一个family键插入到原始顶级对象的每个子元素中，并带有该元素的键值（例如windows124第一个元素）。然后它返回子元素作为一个集合，这正是您想要的。

问题中给出的文档的输出：

{"updated":"2015-01-14","attribution":[],"description":"","notes":[],"alt_names":[],"sources":[],"urls":["google.com","google.co.uk"],"common_name":"test","uuid":"7259334c-3218-4259-aaab-896d87507f4f","family":"windows124"}
{"updated":"","attribution":["Naifdddkoscn"],"description":"","notes":[],"alt_names":[],"sources":[],"urls":["https://example.com/1.pdf","https://example.com/1.pdf","https://example.com/1.pdf"],"common_name":"121212","uuid":"009db412-762d-4256-8df9-eb213be01ffd","family":"linux124"}
{"updated":"2018-07-31","attribution":[],"description":"","notes":[],"alt_names":[],"sources":[],"urls":["https://example.com/1.pdf"],"common_name":"test343","uuid":"4d8da0af-cfd7-4990-b211-af0e990vfda0","family":"wikipedia123"}

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