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快速杀死包含word的进程

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快速杀死包含word的进程 
$ ps aux | grep ruby
user              1565   3.7  0.1  4307464  17696 s000  S+    7:31AM   0:00.61 /Users/user/.rbenv/versions/2.3.1/bin/ruby bin/rails c
user              1579   0.0  0.0  4268020    788 s001  S+    7:31AM   0:00.00 grep ruby
user              1489   0.0  0.0        0      0   ??  Z     7:29AM   0:00.00 (ruby)

如何快速终止所有这些进程？

我尝试过的：

kill -9 `ps aux | grep ruby`

我的环境：

$ bash --version
GNU bash, version 3.2.57(1)-release (x86_64-apple-darwin18)
Copyright (C) 2007 Free Software Foundation, Inc.
$ uname -a
Darwin MacBook-Pro.local 18.0.0 Darwin Kernel Version 18.0.0: Wed Aug 22 20:13:40 PDT 2018; root:xnu-4903.201.2~1/RELEASE_X86_64 x86_64
$

答案1

正如 Haxiel 评论的那样，我的建议是使用杀戮:

pkill -9 ruby

答案2

kill $(ps aux | grep ruby | grep -v grep | awk '{print $2}' | xargs)

for p in $(ps aux | grep ruby | grep -v grep | awk '{print $2}'); do kill $p; done

kill9有需要的话可以替换kill。

答案3

我尝试使用以下命令

ps -eaf | grep -i ruby| grep -iv 'grep'| awk '{print "kill -9" " " $2}'| sh

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