Linux 中的 Echo 正常运行时间

Linux 中的 Echo 正常运行时间

我需要确定系统上的用户数,如果该值大于或等于脚本中设置的用户计数变量,则打印出系统已运行的时间以及系统负载是多少。我如何将其添加到我的 echo 中?在我的代码中

#!/bin/sh
#
# Syswatch       Shows a variety of different task based on my Linux System
#
# description:   This script will first check the percentage of the filesystem
#                being used. If the percentage is above ___, the root user will
#                be emailed. There will be 4 things echoed in this script. The
#                first thing being the amount of free/total memory being used,
#                second the amount of free/total swap space being used, the
#                third is the user count, and the last thing is the amount
#                of time that the system has been up for and the system load.

#Prints amount of Free/Total Memory and Swap

free -t -m | grep "Total" | awk '{ print "Free/Total Memory : "$4"/"$2"  MB";}'
free -t -m | grep "Swap" | awk '{ print "Free/Total Swap : "$4"/"$2" MB";}'

#Displays the user count for the system

printf "User count is at %d\n" $(who | wc -l)

count=$(who | wc -l)
if [ $count -eq 2 ]
then
  echo "The system has been up for _______  with a system load of average: __"
fi

exit 0

答案1

uptime提供您要查找的信息,因此您可以直接调用它而不是echo

> uptime
 23:40pm  up 13 days  8:09,  6 users,  load average: 1.28, 1.25, 1.23

如果格式不令人满意,你可以echo用类似以下内容替换该语句:

uptime | sed 's/.*up/The system has been up for/' | sed 's/,.*load/ with a system load/'

或者,如果您真的想使用,echo您可以解析uptime输出以获取您想要的值(就像您对 所做的那样$count)并在 echo 语句中使用它们。

附注:

  • 一旦您可以重新排列代码以便不再调用它,您就已经获得了用户数:
count=$(who | wc -l)
printf "User count is at %d\n" $count
  • “大于或等于”运算符-ge不是-eq

如果[$count-ge 2]

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