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awk 在固定列中打印数据

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awk 在固定列中打印数据

我想打印固定列中的数据。我的意思是列应该像表格中一样。我使用了 printf。输入：

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AWK：

{
for(i=1;i<=5;i++){
printf "%20s",$i
if (i==5){print "\n"}}
}

结果

          To                find         information                 use                 the



        Find           something                 you               would                like



        Both            official       documentation                  as                well

列的左侧和下方有大量空间。还有其他方法可以显示吗？

答案1

awk -v numlines=$( wc -l t | awk '{print $1}' ) '{ if (NF>0) { for (i=1;i<=5;i++) printf("%-20s ",$i) ; if (NR != numlines) { print "" } } }' inputfile

'numlines=$(' 部分将输入文件中的行数放入 awk 可用的名为 numlines 的变量中。'NF>0' 确保忽略空行。'printf(%-20s' 确保字段左对齐且宽度为 20 个字符。'NR != numlines' 在文件末尾以外的地方打印换行符。

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