#!/bin/sh
# This is comment!
echo Hello World
for file1 in /C:/Users/shubham.tomar/Desktop/Shell/Test1/*;
do
filename1=$(basename "$file1")
echo $filename1
echo "------------------------"
for file2 in /C:/Users/shubham.tomar/Desktop/Shell/Test2/*;
do
filename2=$(basename "$file2")
echo $filename2
if [["filename1" = "filename2"]]; then
echo "---File matched---"
else
mv -f /C:/Users/shubham.tomar/Desktop/Shell/Test2/$filename2 /C:/Users/shubham.tomar/Desktop/Shell/Moved/
fi
echo "--------------File Moved-----------"
done
done
**
关于问题的注释
**
在 ex 的特定路径中有一些文件:Desktop/Test1 和 Downloads/Test2 我想编写一个 shell 脚本,将 Test2 中而不是 Test1 中存在的所有文件移动到 ex 的路径:Documents/MovedFiles 文件可能是任何类型
答案1
sf() {
# find all files in the directory $1 non-recursively and sort them
find $1 -maxdepth 1 -type f printf '%f\n' | sort
}
然后运行
join -v 1 <(sf Tes2) <(sf Tes1) | xargs -d '\n' -I file mv Tes2/file MovedFiles/
管道的左操作数查找Tes2
该目录中不存在的所有文件Tes1
。
然后管道的右操作数将这些文件移动到目录中MovedFiles
。
答案2
使用嵌套的 for 循环是错误的。您不想将Test1
中的每个文件名与Test2
.
编辑:一些用于调试和避免使用 file 的附加脚本行*
。
#!/bin/sh
# Check if this is correct
dir1="/C:/Users/shubham.tomar/Desktop/Shell/Test1"
# maybe you have to write
# dir1="/c/Users/shubham.tomar/Desktop/Shell/Test1"
dir2="/C:/Users/shubham.tomar/Desktop/Shell/Test2"
targetdir="/C:/Users/shubham.tomar/Desktop/Shell/Moved"
# for debugging
echo contents of dir1 $dir1
ls "$dir1"
echo contents of dir2 $dir2
ls "$dir2"
# loop over all files in $dir2 because you want to find files in $dir2 that are not in $dir1
for file2 in "$dir2"/*
do
# if $dir2 does not exist or is empty we will get something like file2="/C:/Users/shubham.tomar/Desktop/Shell/Test2/*"
# That's why check if the file exists
if [ -f "$file2" ]
then
filename2=$(basename "$file2")
echo $filename2
echo "------------------------"
# does a file with the same basename exist in $dir1?
if [ ! -f "$dir1/$filename2" ]
then
# using "$targetdir"/." makes sure you get an error if $targetdir is a file instead of a directory
mv -f "$file2" "$targetdir"/.
echo "--------------File Moved-----------"
else
echo "file with the same name exists in $dir1"
fi
fi
done
如果您想先尝试此操作而不实际移动文件,您可以替换该行
mv -f "$file2" "$targetdir"/.
和
echo mv -f "$file2" "$targetdir"/.