通过命令行将密码多次传送到命令

通过命令行将密码多次传送到命令

我正在运行Ubuntu 18.04bash我想将密码传递给运行的命令sudo,但是一旦运行,即密码通过管道传输到命令(python3运行命令app),它会要求输入密码两次,我正在尝试通过以下方式做到这一点:

echo "passphrase" | echo "passphrase" | echo $password | sudo command

但它似乎不起作用。

该命令的输出如下:

sudo python3 app.py
Enter PEM pass phrase:
 * Serving Flask app "app" (lazy loading)
 * Environment: production
   WARNING: Do not use the development server in a production environment.
   Use a production WSGI server instead.
 * Debug mode: on
 * Running on https://127.0.0.1:443/ (Press CTRL+C to quit)
 * Restarting with stat
Enter PEM pass phrase:
 * Debugger is active!
 * Debugger PIN: 157-564-730
127.0.0.1 - - [30/Jan/2019 18:29:44] "GET / HTTP/1.1" 200 -
127.0.0.1 - - [30/Jan/2019 18:29:45] "GET /static/style.css HTTP/1.1" 200 -
127.0.0.1 - - [30/Jan/2019 18:29:45] "GET /static/vendor/bootstrap/css/bootstrap.css HTTP/1.1" 200 -
127.0.0.1 - - [30/Jan/2019 18:29:45] "GET /static/css/simple-sidebar.css HTTP/1.1" 200 -
127.0.0.1 - - [30/Jan/2019 18:29:45] "GET /static/vendor/jquery/jquery.min.js HTTP/1.1" 200 -
127.0.0.1 - - [30/Jan/2019 18:29:45] "GET /static/vendor/bootstrap/js/bootstrap.bundle.min.js HTTP/1.1" 200 -
127.0.0.1 - - [30/Jan/2019 18:29:45] "GET /favicon.ico HTTP/1.1" 404 -

有谁知道如何通过unixbash 脚本中的命令来执行此操作?

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