如何将远程公共IP（通过wireguard）分配给lxc容器

Question

我拥有的：

LXC主机

# ifconfig
wg1: flags=209<UP,POINTOPOINT,RUNNING,NOARP>  mtu 1420
inet 192.168.7.2  netmask 255.255.255.0  destination 192.168.7.2
...

enp2s0: flags=4163<UP,BROADCAST,RUNNING,MULTICAST>  mtu 1500
inet 192.168.1.110  netmask 255.255.255.0  broadcast 192.168.1.255
...

lxdbr0: flags=4163<UP,BROADCAST,RUNNING,MULTICAST>  mtu 1500
inet 10.7.56.1  netmask 255.255.255.0  broadcast 0.0.0.0
...

/etc/wireguard/wg1.conf

[Interface]
PrivateKey = my_private_key
Address = 192.168.7.2/24

[Peer]
PublicKey = my_public_key
AllowedIPs = 0.0.0.0/0
Endpoint = my_remote_server_ipv4:51194
PersistentKeepalive = 15

# route -n
Kernel IP routing table
Destination     Gateway         Genmask         Flags Metric Ref    Use Iface
0.0.0.0         192.168.1.1     0.0.0.0         UG    100    0        0 enp2s0
10.7.56.0       0.0.0.0         255.255.255.0   U     0      0        0 lxdbr0
192.168.1.0     0.0.0.0         255.255.255.0   U     0      0        0 enp2s0
192.168.1.1     0.0.0.0         255.255.255.255 UH    100    0        0 enp2s0
192.168.7.0     0.0.0.0         255.255.255.0   U     0      0        0 wg1

LXC集装箱

# curl ifconfig.me
my_remote_server_ipv4

一切都很好，但是：

# ifconfig
eth0: flags=4163<UP,BROADCAST,RUNNING,MULTICAST>  mtu 1500
inet 10.7.56.100  netmask 255.255.255.0  broadcast 10.7.56.255
...

我想要的是：

# ifconfig
eth0: flags=4163<UP,BROADCAST,RUNNING,MULTICAST>  mtu 1500
inet my_remote_server_ipv4  netmask 255.255.255.0  broadcast ...
...

我想在不更改容器中任何内容的情况下执行此操作。

更新。我想为我的家庭 lxc 容器分配一个公共 IP（由我的远程服务器拥有）。看来是不可能了...