我需要编写一个脚本来查看 /etc/passwd 10 x 10 的页码。因此按下按钮后它将显示接下来的 10 行。我应该使用什么命令?尝试检查 awk、head、tail、命令,但没有找到解决方案。
#!/bin/bash
awk -F":" 'BEGIN { print "--------------------------------------------------"
printf "%-20s %-10s %-3s\n","USERNAME","GUID","DIRECTORY"
print "--------------------------------------------------"
}
NR==1, NR==10 {printf "%-20s %-10s %-3s\n", $1, $4, $7} ' /etc/passwd
答案1
getline rc < "-"
每第 10 行添加一次。要抑制换行符,请使用以下命令将光标向上移动一行system("tput cuu1")
:
awk -F":" '
BEGIN { print "--------------------------------------------------"
printf "%-20s %-10s %-3s\n","USERNAME","GUID","DIRECTORY"
print "--------------------------------------------------" }
!(NR%10) { getline rc < "-"; system("tput cuu1") }
{ printf "%-20s %-10s %-3s\n", $1, $4, $7 }
' /etc/passwd
要添加页码,您可以使用:
awk -F":" -v TNR=$(wc -l < /etc/passwd) '
BEGIN { NUM_PAGES=TNR/10+1
print "--------------------------------------------------"
printf "%-20s %-10s %-3s\n","USERNAME","GUID","DIRECTORY"
print "--------------------------------------------------" }
!(NR%10) { PAGE++
printf "--- Page %d of %d ---",PAGE,NUM_PAGES
getline rc < "-"; system("tput cuu1") }
{ printf "%-20s %-10s %-3s\n", $1, $4, $7 }
' /etc/passwd