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如何唯一打印此脚本的输出行，并为每一行打印重复次数

tag-icon • tag-icon linux bash shell-script
如何唯一打印此脚本的输出行，并为每一行打印重复次数 
#!/bin/bash

who |grep "10\.1\.109" | grep -v berianho | cut -f1 -d " " | sort -n|

while read user 
do 
    grep -a ^$user: /etc/passwd | cut -f5 -d:
done

答案1

一个简单的 Perl 脚本...

#!/usr/bin/perl

my %hash;

open FH, 'who |' or die;
while ( <FH> ) {
   $hash{$1}++ if /^(\S+).*(10\.\d+\.\d+\.\d+)/;
}
close FH;

while ( ($k,$v) = each %hash ) {
   printf "%3d %s\n", $v, $k;
}

exit;

答案2

这是我对你想做的事情的假设。

#!/bin/bash
list="$(who |grep "10\.1\.109" | grep -v berianho | cut -f1 -d " ")"
unique="$(echo ${list} | tr ' ' '\n' | sort | uniq)"

for student in $unique
do
  echo "Student $(grep -a ^${student}: /etc/passwd | cut -f5 -d ":" ) has number of $(echo "$list" | tr ' ' '\n' | grep ${student} | wc -l) logins."
done

示例输出假设 AAA（passwd 上的名称为 AAA AAA）有 3 个，BBB（passwd 上的名称为 BBB BBB）有，CC（passwd 上的名称为 CCC CCC）有 1 个条目who。输出必须是：

Student AAA AAA has number of 3 logins.
Student BBB BBB has number of 2 logins.
Student CCC CCC has number of 1 logins.

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