在下面的脚本中,我要求用户输入日期范围并应用该范围来过滤命令的结果find
。该命令适用于名称包含日期的日志文件,如filename-YYYYMMDD.gz
.一旦识别出此类文件,就会将其复制到新目录中。
到目前为止,我所拥有的(例如日期范围之类的)-newermt 20190820 ! -newermt 20190826
不会在 25 日或 26 日复制文件。
更新:
#!/bin/bash
#Take input from user
read -p "Enter year (YYYY): " Y
read -p "Enter start month: " SM
read -p "Enter start day: " SD
read -p "Enter end month: " EM
read -p "Enter end day: " ED
read -p "Enter copy destination directory (with absolute path): " new_directory
# pad month and day numbers with zero to make the string 2 character long
SD="$(printf '%02d' $SD)"
SM="$(printf '%02d' $SM)"
ED="$(printf '%02d' $ED)"
EM="$(printf '%02d' $EM)"
# Make sure that the new directory exists
#mkdir -p new_directory
# Place the result of your filtered `find` in an array,
# but, before, make sure you set:
#IFS='\n' # in case some file name stored in the array contains a space
array=(
$(find /directory/log/ -name "test.file-*.gz" -execdir bash -c '
filedate="$(basename ${0#./test.file-} .gz)";
if [[ $filedate -gt $Y$SM$SD ]] && [[ $filedate -lt $Y$EM$ED ]]; then
basename $0
fi' {} \;
)
)
# loop over array, to copy selected files to destination directory
for i in "${array[@]}"; do
# ensure that destination directory has full path
cp "$i" "$new_directory"
done
我知道 find -newermt 命令正在查找在给定日期修改的文件而不是文件名。如果您知道有更好的方法,我将非常感激。
答案1
根据文件名中包含的日期查找文件
如果你的意思是真的 要过滤文件名中的日期,那么您可以执行以下操作:
#!/bin/bash
read -p "Enter year (YYYY): " Y
read -p "Enter start month number: " SM
read -p "Enter start day number: " SD
read -p "Enter end month number: " EM
read -p "Enter end day number: " ED
read -p "Enter copy destination directory (with absolute path): " new_directory
# Do some rule-based checking here. I.e. input variables above
# should conform to expected formats...
# pad month and day numbers with zero to make the string 2 character long
SD="$(printf '%02d' $SD)"
SM="$(printf '%02d' $SM)"
ED="$(printf '%02d' $ED)"
EM="$(printf '%02d' $EM)"
# Make sure that the new directory exists
mkdir -p "$new_directory"
# Place the result of your filtered `find` in an array,
# but, before, make sure you set:
IFS=$'\n' # in case some file name stored in the array contains a space
sdate="$Y$SM$SD"
edate="$Y$EM$ED"
array=(
$(find /directory/log -name "filename-*.gz" -execdir bash -c '
filedate="$(basename ${0#./filename-} .gz)";
if (("${filedate:-0}" >= "${1:-0}")) &&
(("${filedate:-0}" <= "${2:-0}")); then
echo "$0"
fi' {} "$sdate" "$edate" \;)
)
# loop over array, to copy selected files to destination directory
#for i in "${array[@]}"; do
# # ensure that destination directory has full path
# cp "$i" "$new_directory"
#done
# ... or much cheaper than a loop, if you only need to copy...
cp "${array[@]}" "$new_directory"