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尝试通过嵌套 for 循环列出 bash 4 中的属性

tag-icon • tag-icon linux bash bash-scripting centos-7
尝试通过嵌套 for 循环列出 bash 4 中的属性

这可能很难解释，但我还是想试一试。此代码片段在 bash 5.0.16 中有效，但在 4.2.46 中无效

我有一个数组 basicHosts=(host1 host2 host3)，这是一个动态生成的数组，名称随时可能更改。我已使用此数组创建 3 个变量，其名称是 basicHosts 中的值。现在我有这个：

host1=(Name CPU Memory IP)
host2=(Name CPU Memory IP)
host3=(Name CPU Memory IP)

我想要做的是循环遍历 basicHosts 中定义的每个变量并打印出值。下面是我在 bash 5 中尝试过的方法

#At this point each host should have its own matrix
#Now we need to set values for each host
echo "Here is what the hostname matrix looks like"

for host in "${basicHosts[@]}"
    do
        temp=$host
        for attr in "${temp[@]}"
            do
                echo $attr
            done
    done

我是 Bash 新手，请原谅我的格式不好。只是想边做边学。希望你们能给我一些建议。

编辑：完整代码

#!/bin/bash
clear
hostSet="True"
defaultSet="False"

declare -a basicHosts
basicHosts=(host1 host2 host3)


clear
echo "Hello, below are the default hosts that will be created
"
declare -i i=0

for hosts in "${basicHosts[@]}"
do
    echo "$i: $hosts"
    i=$i+1
done

echo "Hosts are Set"


#Going to start creating the arrays based off of the host names

for host in "${basicHosts[@]}"
    do
        declare -a $host
        eval "$host=(Name CPU Memory)"
    done

echo "Variable matrix created"
#At this point each host should have its own matrix
#Now we need to set values for each host
echo "Here is what the hostname matrix looks like"


for host in "${basicHosts[@]}"
    do
        typeset temp="$host"

        echo $host
        for attribute in "${temp[@]}"
            do
                echo "${host[$attribute]}"
            done


    done

答案1

这里的问题在于将 host1、host2 和 host3 声明为数组并不是变量到基本主机数组并使用级联，这是解决该问题的另一种方法：

#!/usr/bin/bash
#At this point each host should have its own matrix
#Now we need to set values for each host
echo "Here is what the hostname matrix looks like"
declare -a basicHosts

## allhosts array here contains n hosts 
for host in allhosts ; do 
    # You can make any treatment here
    basicHosts+=( ${host[*]} )
done

for host in "${basicHosts[@]}" ; do
        for temp in "${host[@]}" ; do
                  echo "${host[$temp]}"
        done
done

编辑 ：

自上次编辑以来，每个主机都应该是可迭代的，并且其上的每个值（名称、CPU、内存）也应该是可迭代的。这可以使用关联数组 + 字符串到数组的转换来实现，以下是您要使用的代码的更新。

#!/bin/bash
clear
hostSet="True"
defaultSet="False"

declare -a basicHosts
basicHosts=(host1 host2 host3)
clear
echo "Hello, below are the default hosts that will be created
"
declare -i i=0

for hosts in "${basicHosts[@]}"
do
    echo "$i: $hosts"
    i=$i+1
done

echo "Hosts are Set"
#Going to start creating the arrays based off of the host names
declare -A results
for host in "${basicHosts[@]}"
    do  
        values="Name CPU Memory"
        arrayvalues=(${values})
        results+=( ["$host"]="${arrayvalues[@]}")

    done
echo "Variable matrix created"
#At this point each host should have its own matrix
#Now we need to set values for each host
echo "Here is what the hostname matrix looks like"
echo "---------------------------------"
array=(${results[${host}]})
for host in "${!results[@]}" ; do
echo -ne "${host} : "
    for value in "${array[@]}" ;do 
        echo -ne "$value - "
    done
    echo -e "\n"
done
echo "---------------------------------"

输出应如下所示：

Here is what the hostname matrix looks like
---------------------------------
host2 : Name - CPU - Memory -

host3 : Name - CPU - Memory -

host1 : Name - CPU - Memory -

---------------------------------

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