我想根据字母顺序更改列数据的顺序
输入
c,a,b
e,k,d
输出
a,b,c
d,e,k
目前,我正在使用下面的代码
awk -F"," -v OFS="," '{
if($1<=$2 && $2<=$3)
{print $1,$2,$3}
else if($1<=$2 && $3<=$2)
{print $1,$3,$2}
else if($2<=$1 && $1<=$3)
{print $2,$1,$3}
else if($2<=$1 && $3<=$1)
{print $2,$3,$1}
else if($3<=$2 && $2<=$1)
{print $3,$2,$1}
else
{print $3,$1,$2}}' test.txt
您能帮我提供一个更简单的解决方案来处理具有 4 列或更多列的文件吗
答案1
如果您同意perl
:
$ perl -F, -lane 'print join ",", sort @F' ip.txt
a,b,c
d,e,k
-F,
指定要分割的输入行,
作为分隔符,结果可通过@F
数组获得
sort @F
join
将按字母顺序排序,结果数组将使用,
分隔符进行组合
和GNU awk
$ awk 'BEGIN{PROCINFO["sorted_in"] = "@val_str_asc"}
{s = ""; c=0; split($0,a,",");
for(k in a) s = c++ ? s "," a[k] : a[k];
print s}' ip.txt
a,b,c
d,e,k
看gawk 手册:使用预定义的数组扫描顺序有关上面使用的数组排序的详细信息
答案2
使用 GNU awk 进行排序:
$ cat tst.awk
BEGIN {
FS=OFS=","
}
{
sub(/\r$/,"")
print sort($0)
}
function sort(inStr, arr,idx,sep,outStr) {
PROCINFO["sorted_in"] = "@val_str_asc"
split(inStr,arr)
for (idx in arr) {
outStr = outStr sep arr[idx]
sep = OFS
}
return outStr
}
$ awk -f tst.awk file
a,b,c
d,e,k
或使用任何 awk,但执行速度会慢得多,因为它会生成一个 shell 来sort
为每行输入调用 UNIX:
$ cat tst.awk
BEGIN {
FS=OFS=","
}
{
sub(/\r$/,"")
print sort($0)
}
function sort(inStr, cmd,line,sep,outStr) {
gsub(/,/,"\n",inStr)
cmd = "printf \047%s\n\047 \047" inStr "\047 | sort"
while ( (cmd | getline line) > 0 ) {
outStr = outStr sep line
sep = OFS
}
close(cmd)
return outStr
}
$ awk -f tst.awk file
a,b,c
d,e,k
这sub(/\r$/,"")
是因为您发布的示例输入中有 DOS 行结尾,但发布的预期输出中没有。
答案3
perl -nlE 'say join ",", sort split ","' file.txt
解释:
for each line like "r,d,a":
"r,d,a"
↓ split "," it
("r","d","a")
↓ sort it
("a","d","r")
↓ join "," it
"a,d,r"
say it