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Shell 脚本：语法错误：“;;”意外（期待“fi”）

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Shell 脚本：语法错误：“;;”意外（期待“fi”）

我一生都无法弄清楚为什么会失败，所以希望这里有人能对此有所启发：

#!/bin/sh

NAME=Container

if [ -d "/mnt/SSD/docker" ]; then
    if [ ! -d "/mnt/SSD/docker/$NAME/data" ]; then
        mkdir -p /mnt/SSD/docker/$NAME/data
    fi
    printf "\nPlease select installation method:\n\n"
    while true; do
        read -p "1. Re-create existing container
2. Create new container: " CHOICE
        case $CHOICE in
            1 )
            if [ "$(docker ps -a | grep $NAME)" ]; then
            IP=$(docker inspect -f '{{range .NetworkSettings.Networks}}{{.IPAddress}}{{end}}' $NAME)
            MAC=$(docker inspect -f '{{range .NetworkSettings.Networks}}{{.MacAddress}}{{end}}' $NAME)
            docker stop $NAME; docker rm $NAME; docker image rm repo/image
            break;;
            else
                printf "\nNo existing container found, going back to menu!\n\n";;
            fi
            2 )
            read -p 'Please enter the IP-address to use: ' IP
            read -p 'Please enter the MAC-address to use: ' MAC
            break;;
            * )
            printf "\nIncorrect or no selection made. Please enter 1 or 2.\n\n";;
        esac
    done
    docker run -d \
    -e JVM_HEAP=1024m -e TZ=Europe/Stockholm \
    --hostname=$NAME \
    --ip=$IP \
    --mac-address=$MAC \
    --name=$NAME --network=macvlan \
    --restart=always \
    -v /mnt/SSD/docker/$NAME/data:/$NAME/data \
    -v /mnt/HDD/Storage:/mnt/HDD/Storage \
    repo/image
else
    logger "ZFS pool SSD is not mounted; aborting $0!"
fi

binarysta 的答案让我克服了语法错误，但现在 case 语句中既没有使用break也没有使用exit，脚本根本就不再做它应该做的事情了。

选择 1. 如果容器存在（break;;），则应该在 case 语句之后运行命令，但如果容器不存在，则返回到菜单（;;）或退出脚本（exit;;）。

如果我使用break而不是;;无论我选择什么，它都会运行命令，而 ;;将返回到菜单并且永远不会在 case 之后运行命令。

答案1

case语句中有一些语法错误。

#!/bin/sh

NAME=Container

if [ -d "/mnt/SSD/docker" ]; then
    if [ ! -d "/mnt/SSD/docker/$NAME/data" ]; then
        mkdir -p /mnt/SSD/docker/$NAME/data
    fi
    printf "\nPlease select installation method:\n\n"
    while true; do
        read -p "1. Re-create existing container
2. Create new container: " CHOICE
        case $CHOICE in
            1 )
            if [ "$(docker ps -a | grep $NAME)" ]; then
            IP=$(docker inspect -f '{{range .NetworkSettings.Networks}}{{.IPAddress}}{{end}}' $NAME)
            MAC=$(docker inspect -f '{{range .NetworkSettings.Networks}}{{.MacAddress}}{{end}}' $NAME)
            docker stop $NAME; docker rm $NAME; docker image rm repo/image           
            else
                printf "\nNo existing container found, going back to menu!\n\n"
            fi
        ;;
            2 )
            read -p 'Please enter the IP-address to use: ' IP
            read -p 'Please enter the MAC-address to use: ' MAC
            ;;
            * )
            printf "\nIncorrect or no selection made. Please enter 1 or 2.\n\n"
        ;;
        esac
    done
    docker run -d \
    -e JVM_HEAP=1024m -e TZ=Europe/Stockholm \
    --hostname=$NAME \
    --ip=$IP \
    --mac-address=$MAC \
    --name=$NAME --network=macvlan \
    --restart=always \
    -v /mnt/SSD/docker/$NAME/data:/$NAME/data \
    -v /mnt/HDD/Storage:/mnt/HDD/Storage \
    repo/image
else
    logger "ZFS pool SSD is not mounted; aborting $0!"
fi

答案2

斯蒙基，;;是为了案件的分离。它们必须处于该级别，而不是在 if 内。那里有一个语法错误。所以在 if 你只做 'break' 和 ;; 中在 case 的末尾（if 之后）

希望有帮助。

#!/bin/sh

NAME=Container

    while true; do
        read -p "1. Re-create existing container
2. Create new container: " CHOICE
        case $CHOICE in
            1 )
              echo 1 gekozen
        if [ "y" = "x" ] 
        then
          echo x
        else
          echo stop
          break
        fi
        ;;
            2 )
            echo 2 gekozen
            read -p 'Please enter the IP-address to use: ' IP
            read -p 'Please enter the MAC-address to use: ' MAC
        echo IP is $IP
        echo MAC is $MAC
        break;;
            * )
            printf "\nIncorrect or no selection made. Please enter 1 or 2.\n\n"
        ;;
        esac
    done

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