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sed：-e表达式#3，字符59：“s”的未知选项

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sed：-e表达式#3，字符59：“s”的未知选项

我正在编写一个脚本来替换 C++ 代码中的三行输入。这是我想要更改其输入的 C++ 代码片段：

char outputFileName_ForBlueEdge[50] = "BlueEdge_SetA_PeriodRange1.dat"; //File with model parameters on the blue edge
    char outputFileName_ForPositiveGrowthModels[50] = "PostiveGrowth_SetA_PeriodRange1.dat"; //File with model parameters that have positve growth rates
    char log_directory_prefix[30] = "LOGS_A/LOGS_A"; //Prefix to log_directory, suffix is model number. This is where LINA file should be

这是 bash 脚本的最小可重现版本：

dir=$PWD
cplusplus_plotter="$dir"/BlueEdge_Plotter_V7.cpp

#Set B
  sed -i \
    -e "s/^\([[:blank:]]*char outputFileName_ForBlueEdge[50]\).*/\1 = "BlueEdge_SetB_PeriodRange1.dat"/i" \
    -e "s/^\([[:blank:]]*char outputFileName_ForPositiveGrowthModels[50]\).*/\1 = "PostiveGrowth_SetB_PeriodRange1.dat"/i" \
    -e "s/^\([[:blank:]]*log_directory_prefix[30]\).*/\1 = "LOGS_B/LOGS_B"/i" \
    "$cplusplus_plotter"

但是，C++ 文件永远不会改变，并且我不断收到错误：

sed: -e expression #3, char 59: unknown option to `s'

答案1

像这样：

  sed -i \
    -e 's/^\([[:blank:]]*char outputFileName_ForBlueEdge\[50\]\).*/\1 = "BlueEdge_SetB_PeriodRange1.dat"/i' \
    -e 's/^\([[:blank:]]*char outputFileName_ForPositiveGrowthModels\[50\]\).*/\1 = "PostiveGrowth_SetB_PeriodRange1.dat"/i' \
    -e 's!^\([[:blank:]]*log_directory_prefix\[30\]\).*!\1 = "LOGS_B/LOGS_B"!i' \
    "$cplusplus_plotter"

您可以选择所需的分隔符（在 ascii 表中）。

我选择!最后一个 sed 命令，因为你有 4 /。

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