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使用sed删除匹配关键字前面的字符

tag-icon • tag-icon shell awk sed
使用sed删除匹配关键字前面的字符

我有一个如下所示的文本。

<DIV>SOFTWARE V1.0.1.0.RDZCUAJ DOWNLOAD</DIV>
<DIV>...</DIV>
<DIV>...</DIV>
<DIV>SOFTWARE V1.0.2.0.VWZMXQE DOWNLOAD</DIV>
<DIV>...</DIV>
<DIV>...</DIV>
<DIV>SOFTWARE V1.0.3.0.GSVZQKE DOWNLOAD</DIV>
<DIV>...</DIV>
<DIV>...</DIV>
<DIV>SOFTWARE V1.0.4.0.UIUVAZD DOWNLOAD</DIV>
<DIV>...</DIV>
<DIV>...</DIV>
<DIV>SOFTWARE V1.0.5.0.ELBXBGB DOWNLOAD</DIV>
<DIV>...</DIV>
<DIV>...</DIV>

我需要删除前面的8个字符DOWNLOAD</DIV>，最终看起来像这样。

<DIV>SOFTWARE V1.0.1.0 DOWNLOAD</DIV>
<DIV>...</DIV>
<DIV>...</DIV>
<DIV>SOFTWARE V1.0.2.0 DOWNLOAD</DIV>
<DIV>...</DIV>
<DIV>...</DIV>
<DIV>SOFTWARE V1.0.3.0 DOWNLOAD</DIV>
<DIV>...</DIV>
<DIV>...</DIV>
<DIV>SOFTWARE V1.0.4.0 DOWNLOAD</DIV>
<DIV>...</DIV>
<DIV>...</DIV>
<DIV>SOFTWARE V1.0.5.0 DOWNLOAD</DIV>
<DIV>...</DIV>
<DIV>...</DIV>

是否可以使用 sed 或 awk 命令来完成此操作？

提前感谢任何帮助！

答案1

一个非常简单的方法如下：

$ sed 's,.........DOWNLOAD</DIV>, DOWNLOAD</DIV>,g' input.txt
<DIV>SOFTWARE V1.0.1.0 DOWNLOAD</DIV>
<DIV>...</DIV>
<DIV>...</DIV>
<DIV>SOFTWARE V1.0.2.0 DOWNLOAD</DIV>
<DIV>...</DIV>
<DIV>...</DIV>
<DIV>SOFTWARE V1.0.3.0 DOWNLOAD</DIV>
<DIV>...</DIV>
<DIV>...</DIV>
<DIV>SOFTWARE V1.0.4.0 DOWNLOAD</DIV>
<DIV>...</DIV>
<DIV>...</DIV>
<DIV>SOFTWARE V1.0.5.0 DOWNLOAD</DIV>
<DIV>...</DIV>
<DIV>...</DIV>

将前面的9个字符替换DOWNLOAD</DIV>为DOWNLOAD</DIV>

答案2

对于必须启用 ERE 的 sed -E（例如 GNU sed 和 BSD/OSX sed）：

sed -E 's:.{8}( DOWNLOAD</DIV>):\1:' file

否则对于任何 POSIX sed：

sed 's:.\{8\}\( DOWNLOAD</DIV>\):\1:' file

例如

$ sed -E 's:.{8}( DOWNLOAD</DIV>):\1:' file
<DIV>SOFTWARE V1.0.1.0 DOWNLOAD</DIV>
<DIV>...</DIV>
<DIV>...</DIV>
<DIV>SOFTWARE V1.0.2.0 DOWNLOAD</DIV>
<DIV>...</DIV>
<DIV>...</DIV>
<DIV>SOFTWARE V1.0.3.0 DOWNLOAD</DIV>
<DIV>...</DIV>
<DIV>...</DIV>
<DIV>SOFTWARE V1.0.4.0 DOWNLOAD</DIV>
<DIV>...</DIV>
<DIV>...</DIV>
<DIV>SOFTWARE V1.0.5.0 DOWNLOAD</DIV>
<DIV>...</DIV>
<DIV>...</DIV>


$ sed 's:.\{8\}\( DOWNLOAD</DIV>\):\1:' file
<DIV>SOFTWARE V1.0.1.0 DOWNLOAD</DIV>
<DIV>...</DIV>
<DIV>...</DIV>
<DIV>SOFTWARE V1.0.2.0 DOWNLOAD</DIV>
<DIV>...</DIV>
<DIV>...</DIV>
<DIV>SOFTWARE V1.0.3.0 DOWNLOAD</DIV>
<DIV>...</DIV>
<DIV>...</DIV>
<DIV>SOFTWARE V1.0.4.0 DOWNLOAD</DIV>
<DIV>...</DIV>
<DIV>...</DIV>
<DIV>SOFTWARE V1.0.5.0 DOWNLOAD</DIV>
<DIV>...</DIV>
<DIV>...</DIV>

答案3

你可以试试这个：

sed 's#SOFTWARE \(.*\)\.[A-Z]\{7\} DOWNLOAD#SOFTWARE \1 DOWNLOAD#' file

答案4

使用 Raku（née Perl6）

~$ raku -pe 's/ <(. ** 8)> <?before " DOWNLOAD</DIV>" $$ >  //;' download.txt
<DIV>SOFTWARE V1.0.1.0 DOWNLOAD</DIV>
<DIV>...</DIV>
<DIV>...</DIV>
<DIV>SOFTWARE V1.0.2.0 DOWNLOAD</DIV>
<DIV>...</DIV>
<DIV>...</DIV>
<DIV>SOFTWARE V1.0.3.0 DOWNLOAD</DIV>
<DIV>...</DIV>
<DIV>...</DIV>
<DIV>SOFTWARE V1.0.4.0 DOWNLOAD</DIV>
<DIV>...</DIV>
<DIV>...</DIV>
<DIV>SOFTWARE V1.0.5.0 DOWNLOAD</DIV>
<DIV>...</DIV>
<DIV>...</DIV>

上面的代码将-pe自动打印标志与s///替换运算符结合使用。在运算符的左半部分内，s///使用零宽度先行断言来查找DOWNLOAD</DIV>结束标记，并且前面的 8 个字符被<(. ** 8)>代码精确捕获（并删除）。

HTH。

https://raku.org
https://docs.raku.org/language/regexes

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