匹配 if 语句中以 -（破折号）开头的全局模式

Question

我无法匹配 if 语句中的“--debug”。
我的目标是符合 POSIX 标准的脚本。

CHANNELS=;
set -- stable beta dev master --debug

echo "DEBUG: Before while $@";
while [ $# -gt 0  ]; do
  echo "DEBUG: Inside while $1";
  if [ ! $1 = -* ]; then
    echo "DEBUG: Inside if $1";
    CHANNELS="$CHANNELS $1";
  fi
  shift;
done
echo "DEBUG: After while $CHANNELS";

实际 -> $CHANNELS 具有“stable beta dev master --debug”
预期 -> $CHANNELS 应具有“stable beta dev master”

Answer 1

模式匹配是通过casePOSIX shell 中的构造完成的：

CHANNELS=
set -- stable beta dev master --debug

echo "DEBUG: Before while $@";
while [ "$#" -gt 0  ]; do
  echo "DEBUG: Inside while $1";
  case $1 in
    (-*) ;;
    (*)
      echo "DEBUG: Inside case (*)"
      CHANNELS="$CHANNELS $1";;
  esac
  shift
done
echo "DEBUG: After while $CHANNELS";