我有以下 bash 函数可以在两个行号之间打印,用于在特定目录中递归地监视文件类型 .texi 和 .org 的文件。
我希望能够提供文件扩展名以使用用作分隔符的-e
选项进行搜索,
。示例:-e el,texi,org
print-region ()
{
# Process command line options
shortopts="hvd:e:p:q:"
longopts="help,version,directory:,extension:,startline:,stoplinene:,"
opts=$(getopt -o "$shortopts" -l "$longopts" -n "$(basename $0)" -- "$@")
if [ $? -eq 0 ]; then
eval "set -- ${opts}"
while [ $# -gt 0 ]; do
case "$1" in
--)
shift; break ;;
-h|-\?|--help)
help=1
local -r f=0
break
;;
-v|--version)
version=1; shift; break ;;
-d|--directory)
local -r dir=$2
shift 2
;;
-e|--extension)
fltype=$2
shift 2
;;
-p|--startline)
local -r na=$2; shift 2 ;;
-q|--stopline)
local -r nb=$2; shift 2 ;;
esac
done
else
shorthelp=1 # getopt returned (and reported) an error.
fi
if [[ $na =~ ^[[:digit:]]+$ ]] && [[ $nb =~ ^[[:digit:]]+$ ]] \
&& [[ -d $dir ]]; then
find "$dir" \( -name \*.org -o -name \*.texi \) \
-exec awk -v a="$na" -v b="$nb" \
'FNR == 1 {s="\n==> "FILENAME" <==\n"; f = 0}
FNR == a {print s; f = 1}
f {print; if (FNR == b) nextfile}' {} +
fi
}
答案1
已经初步尝试了解决方案,并且非常感谢评论。祝贺。
str=$(echo $fltype | tr "," "\n")
nmser=( '(' )
for ext in $str; do
nmser+=( -name "*.$ext" -o )
done
nmser[${#nmser[@]}-1]=')'
printf "nmser:\n"
for i in ${nmser[@]}; do echo $i; done
if [[ $na =~ ^[[:digit:]]+$ ]] && [[ $nb =~ ^[[:digit:]]+$ ]] \
&& [[ -d $dir ]]; then
# `-exec` avoids problems with too many file matches
# `nextfile` stops processing the current input file.
#find "$dir" \( -name \*.org -o -name \*.texi \) \
find "$dir" "${nmser[@]}" \