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如何在bash中使用多个变量

tag-icon • tag-icon bash text-processing
如何在bash中使用多个变量

user.txt我有一个包含以下内容的文件 ( )，有 90 多个用户

  • 示例文件内容 
    user: Ronaldo
id:7
endpoint:manutd.com
user: Messi
id:30
endpoint:psg.com
user: Neymar
id:10
endpoint:psg.com
  • 期望的输出： 
    Ronaldo is in manutd.com and wears no 7
Messi is in psg.com and wears no 30
.
.
    对于所有用户等等

如何通过 Bash 脚本以这种方式打印？

答案1

你可以用这个awk

awk -F: '/user/ {name=$2 " is in "; next} /id/{id="no "$2;next} /endpoint/ {team=$2 " and wears "} {print name, team, id }' $inputfile

输出

 Ronaldo is in  manutd.com and wears  no 7
 Messi is in  psg.com and wears  no 30
 Neymar is in  psg.com and wears  no 10

我假设您的预期大写输出是错误的，但如果不是，请指出这一点。

答案2

和sed：

$ sed -n 'N;N;s/^user: *\(.*\)\nid: *\(.*\)\nendpoint: *\(.*\)/\1 is in \3 and wears no \2/p' file
Ronaldo is in manutd.com and wears no 7
Messi is in psg.com and wears no 30
Neymar is in psg.com and wears no 10

答案3

重击：

declare -A record
while IFS=":$IFS" read -r key value; do
    record[$key]=$value
    if [[ -v 'record[user]' && -v 'record[id]' && -v 'record[endpoint]' ]]; then
        printf '%s is in %s and wears no %s\n' "${record[user]}" "${record[endpoint]}" "${record[id]}"
        record=()
    fi
done < file.content

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