如何“不忙”/dev/sdx?

如何“不忙”/dev/sdx?

我找到了另一个线程,但它很旧,所以我发布...它建议“lsof”来查找阻塞(使繁忙)进程它提示我可以使用“dev/sdf23”,但它不是一个文件。

还有其他“不忙”/dev/sdc 的方法吗?

qy@qy-desktop:~$ lsof +f -- /dev/sdf23
lsof: not a file system: /dev/sdf23
lsof 4.93.2
 latest revision: https://github.com/lsof-org/lsof
 latest FAQ: https://github.com/lsof-org/lsof/blob/master/00FAQ
 latest (non-formatted) man page: https://github.com/lsof-org/lsof/blob/master/Lsof.8
 usage: [-?abhKlnNoOPRtUvVX] [+|-c c] [+|-d s] [+D D] [+|-E] [+|-e s] [+|-f[gG]]
 [-F [f]] [-g [s]] [-i [i]] [+|-L [l]] [+m [m]] [+|-M] [-o [o]] [-p s]
 [+|-r [t]] [-s [p:s]] [-S [t]] [-T [t]] [-u s] [+|-w] [-x [fl]] [--] [names]
Use the ``-h'' option to get more help information.
qy@qy-desktop:~$ 

PS如果这是转发,我很抱歉。我失去了我的帖子的踪迹......

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