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如何在awk中从末尾解析文件

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如何在awk中从末尾解析文件 
#!/bin/sh
if [ $# -ne 8 ]; then
        echo "Usage: sh `basename $0` YYYYMMDD hour min masterid account destination filename forward|backward";
        exit 1;
fi

day=${1}
hour=${2}
min=${3}
masterid=${4}
account=${5}
destination=${6}
file=${7}
if [ "${8}" == "backward" ]; then
        backward="true";
fi

if [ "${backward}" != "true" ]; then
        awk -v day=${day} -v hour=${hour} -v min=${min} -v masterid=${masterid} -v account=${account} -v destination=${destination} -f /var/tmp/selfCross.awk /koba/c/dumper/${file}
else
        tac "/koba/c/dumper/${file}" | awk -v day=${day} -v hour=${hour} -v min=${min} -v masterid=${masterid} -v account=${account} -v destination=${destination} -f /var/tmp/selfCross.awk
fi

如果向后！= true，则工作正常。但是，tac 不知何故不起作用，我该怎么办？它立即返回。我在上面的脚本中做错了什么？

答案1

不是答案，而是提示：使用“true”和“false”命令而不是测试字符串相等性：

backwards=false
if [[ some condition ]]; then backwards=true; fi

if $backwards; then
  do something
else
  do something else
fi

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