每个日期的证书过期报告

每个日期的证书过期报告

您好,我如何对下面的文件进行排序,以便使用证书到期日期来对此进行排序,谢谢

Cluster10*  expire date: Feb 22 23:59:59 2024 GMT
Cluster11*  expire date: Feb  1 23:59:59 2023 GMT
Cluster23*  expire date: Jan 24 23:59:59 2021 GMT
Cluster24*  expire date: May 23 23:59:59 2023 GMT

答案1

装饰-排序-取消装饰:

$ awk -v mths='JanFebMarAprMayJunJulAugSepOctNovDec' '
    { printf "%d%02d%02d%s\t%s\n", $7, (index(mths,$4)+2)/3, $5, $7, $0 }
' file | sort | cut -f2-
Cluster23*  expire date: Jan 24 23:59:59 2021 GMT
Cluster11*  expire date: Feb  1 23:59:59 2023 GMT
Cluster24*  expire date: May 23 23:59:59 2023 GMT
Cluster10*  expire date: Feb 22 23:59:59 2024 GMT

答案2

我将日期转换为 unixtime 然后排序:

$ cat test.txt | while read line; do echo -n "$line|"; date -d "`echo "$line" | cut -c 26-49`" +%s; done | sort -t\| -k2
Cluster23*  expire date: Jan 24 23:59:59 2021 GMT|1611532799
Cluster11*  expire date: Feb  1 23:59:59 2023 GMT|1675295999
Cluster24*  expire date: May 23 23:59:59 2023 GMT|1684886399
Cluster10*  expire date: Feb 22 23:59:59 2024 GMT|1708646399

答案3

Time::Piece模块:

perl -MTime::Piece -nle '
    push @A, $_ ;}{
    print for(sort {
        Time::Piece->strptime(join(" ", (split /  ?/, $a)[3..7]), "%b %d %T %Y %Z")
            <=>
        Time::Piece->strptime(join(" ", (split /  ?/, $b)[3..7]), "%b %d %T %Y %Z")
    } @A)
' sample

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