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使用 sed 或 awk 删除文本文件中以 * 开头的行？

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使用 sed 或 awk 删除文本文件中以 * 开头的行？

我有文本文件，我想要删除该行以 * 开头

我尝试使用 grep，它不起作用。

grep -v '^#'

建议表示赞赏。

\n
OG0018658
                M0~bbe9a2ca8a9915aafa220a87c248a064 |           M1~439516e2a637051372399975c71af47b | 0.009414**
                M0~bbe9a2ca8a9915aafa220a87c248a064 |           M5~d51f0107310c1d9a8cbe5b0305c46986 | 0.009341**
                M0~bbe9a2ca8a9915aafa220a87c248a064 |           M6~462cfd85f3d26c451e0ea388b1ee265e | 0.009341**
                M0~bbe9a2ca8a9915aafa220a87c248a064 |           M7~f3c7a863e871762d7674e5a6f6aa1b0d | 0.009438**
                M0~bbe9a2ca8a9915aafa220a87c248a064 |          M8a~17a2f94c77ce46d91db4dc8a50d30fd7 | 0.034070*
   * Average omega for all tree: 0.167
   * Average omega for all tree: 0.179
   * Sites significantly caracterized
   * Average omega for all tree: 0.179
   * Sites significantly caracterized
   * Average omega for all tree: 0.176
   * Sites significantly caracterized
   * Average omega for all tree: nan
   * Average omega for all tree: 0.175
   * Average omega for all tree: 0.175
   * Average omega for all tree: 0.174
   * Average omega for all tree: 0.174
   * Average omega for all tree: 0.177
   * Average omega for all tree: 0.167
   * Average omega for all tree: 0.179
   * Average omega for all tree: 0.179
   * Average omega for all tree: 0.176
   * Average omega for all tree: nan
   * Average omega for all tree: 0.175
   * Average omega for all tree: 0.175
   * Average omega for all tree: 0.174
   * Average omega for all tree: 0.174
   * Average omega for all tree: 0.177


Modified file


\n
OG0018658
                M0~bbe9a2ca8a9915aafa220a87c248a064 |           M1~439516e2a637051372399975c71af47b | 0.009414**
                M0~bbe9a2ca8a9915aafa220a87c248a064 |           M5~d51f0107310c1d9a8cbe5b0305c46986 | 0.009341**
                M0~bbe9a2ca8a9915aafa220a87c248a064 |           M6~462cfd85f3d26c451e0ea388b1ee265e | 0.009341**
                M0~bbe9a2ca8a9915aafa220a87c248a064 |           M7~f3c7a863e871762d7674e5a6f6aa1b0d | 0.009438**
                M0~bbe9a2ca8a9915aafa220a87c248a064 |          M8a~17a2f94c77ce46d91db4dc8a50d30fd7 | 0.034070*

答案1

简单的 awk 解决方案：

awk '$1!="*"' infile

等效的 sed 解决方案：

sed '/^[[:blank:]]*\*/d' infile

与 grep 中使用的正则表达式相同：

grep -v '^[[:blank:]]*\*' infile

答案2

但它们实际上以一些空白字符开头。

grep -v '^[[:blank:]]*\*' file.txt

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