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运行良好的 bash 脚本在 sh 下给出 read -p no coprocess

tag-icon • tag-icon bash shell android
运行良好的 bash 脚本在 sh 下给出 read -p no coprocess

这个多选菜单在 bash 下工作正常，但是当我在 android 上的 sh 下尝试它时，它失败并出现错误“read -p no coprocess”

欢迎任何建议...

options=("AAA" "BBB" "CCC" "DDD")

menu() {
    echo "Avaliable options:"
    for i in ${!options[@]}; do 
        printf "%3d%s) %s\n" $((i+1)) "${choices[i]:- }" "${options[i]}"
    done
    if [[ "$msg" ]]; then echo "$msg"; fi
}

prompt="Check an option (again to uncheck, ENTER when done): "
while menu && read -rp "$prompt" num && [[ "$num" ]]; do
    [[ "$num" != *[![:digit:]]* ]] &&
    (( num > 0 && num <= ${#options[@]} )) ||
    { msg="Invalid option: $num"; continue; }
    ((num--)); msg="${options[num]} was ${choices[num]:+un}checked"
    [[ "${choices[num]}" ]] && choices[num]="" || choices[num]="+"
done

printf "You selected"; msg=" nothing"
for i in ${!options[@]}; do 
    [[ "${choices[i]}" ]] && { printf " %s" "${options[i]}"; msg=""; }
done

答案1

经过一番谷歌搜索和阅读后，我想我解决了它，至少现在对我来说效果很好:)

sh 喜欢提示符之前的变量：

while menu && read -rp "$prompt" num && [[ "$num" ]]; do

变成：

while menu && read num "$prompt" && [[ "$num" ]]; do

完整代码如下

options=("AAA" "BBB" "CCC" "DDD")

menu() {
    echo "Avaliable options:"
    for i in ${!options[@]}; do 
        printf "%3d%s) %s\n" $((i+1)) "${choices[i]:- }" "${options[i]}"
    done
    if [[ "$msg" ]]; then echo "$msg"; fi
}

prompt="Check an option (again to uncheck, ENTER when done): "
while menu && read num "$prompt" && [[ "$num" ]]; do
    [[ "$num" != *[![:digit:]]* ]] &&
    (( num > 0 && num <= ${#options[@]} )) ||
    { msg="Invalid option: $num"; continue; }
    ((num--)); msg="${options[num]} was ${choices[num]:+un}checked"
    [[ "${choices[num]}" ]] && choices[num]="" || choices[num]="+"
done

printf "You selected"; msg=" nothing"
for i in ${!options[@]}; do 
    [[ "${choices[i]}" ]] && { printf " %s" "${options[i]}"; msg=""; }
done
echo "$msg"

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