递归文件重命名器 - 非常有用的 python 脚本在升级 Python(Pyt2 到 Pyt3)后停止工作。有人能找到并解决问题吗?谢谢你!
例如,这些文件:
'Linux příručka českého uživatele.pdf' 'LINUXTERO příkazy které se vždy hodí.pdf' “Práce s archívy příkazové řádka.pdf” 'Rekurzivní grep.txt'
更改这些文件:
linux_prirucka_ceskeho_uzivatele.pdf' linuxtero_prikazy_ktere_se_vzdy_hodi.pdf prace_s_archivy_prikazove_radka.pdf rekurzivni_grep.txt
程序员是捷克人,所以我必须通过谷歌翻译成英语......
当我启动脚本时,按摩失败,如下所示:
linq@legion5:~/test-renamer/ask_stackexchange_folder$ vycisti.py 文件“/home/linq/bin/vycisti.py”,第 62 行 print "警告:'%s' 仍然不是有效名称" % fileName ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ ^^^^^^ 语法错误:调用“打印”时缺少括号。您的意思是 print(...) 吗?
这是脚本:
#!/usr/bin/python
# -*- coding: utf-8
'''Renames all files and directories in the current directory to
to have some culture. It also works recursively in nested ones
directories. The changes are as follows:
Czech characters -> English
cancels all dashes and spaces at the beginning of the name (damn, what kind
the names make up would deserve a few slaps)
special characters are replaced by '_', I take the hyphen at mercy, but not at the beginning
the (unnecessary) '_' around the hyphen is discarded
multiple '_'s are replaced by a single occurrence
everything will be converted to lowercase
The result should be a title where there are only letters, underscores,
numbers, periods and dashes (but not at the beginning).
It writes exactly what it does to standard output
Usage: vycisti.py [ > logfile ]
'''
import re
import os
import sys
import unicodedata
class RenameFiles:
def __init__(self):
if os.environ.get('OS','') == 'Windows_NT':
self.locale = "cp1250"
else: #probably linux
local = os.environ.get('LANG', '')
if '.' in local: #Fedora way
self.locale = local.split('.')[1]
else: #Debian
self.locale = 'iso-8859-2'
def cleanString(self, what):
'''Gets rid of letters which are not in English alphabet'''
assert type(what) == unicode
normalized = unicodedata.normalize('NFKD', what)
output = ''
for c in normalized:
if not unicodedata.combining(c):
output += c
return output
def cleanName(self, fileName):
'''Convert the givne string into a form which is suitable for a file name'''
assert type(fileName) == str
fileName = self.cleanString(fileName.decode(self.locale))
fileName = re.sub("^[-\ ]+", "", fileName) #delete space or dash at the beginning
invalid_stuff = re.compile(r"[^a-zA-Z0-9_\.-]+") #forbidden characters (non-alfanumerical)
fileName = invalid_stuff.sub("_", fileName.strip()) #replace invalid stuff and spaces by _,
fileName = re.sub("_+", "_", fileName) #squeeze continuous underscores to one _
fileName = re.sub("-+", "-", fileName) #squeeze continuous dashes to one _
fileName = re.sub("_*-_*", "-", fileName) #removes useless '_' round the dash
fileName = re.sub("_*\._*", ".", fileName) #removes useless '_' round the dot
fileName = re.sub("-*\.-*", ".", fileName) #removes useless '-' round the dot
fileName = fileName.lower() #lower case
valid_name=re.compile(r"^[a-z0-9_\.][a-z0-9_\.-]+$") #regular expression for feasible name
if not valid_name.match(fileName):
print "Warning: '%s' is still not valid name" % fileName
return fileName.encode(self.locale)
def renameFile(self, dir, fileName):
'''Public: Renames the file fileName in the directory'''
assert type(fileName) == str
assert type(dir) == str
try:
new = self.cleanName(fileName)
except:
print "Problem: %s %s " % (fileName, sys.exc_info()[0] )
new = ""
if (new != "" and new != fileName):
print "Renaming %s: %s -> %s" % (dir, fileName, new) #kontrolní výpis
os.rename(dir+os.sep+fileName, dir+os.sep+'tmp')
os.rename(dir+os.sep+'tmp', dir+os.sep+new)
return
def process_dir(self, dir):
"""process all files in the folder"""
assert type(dir) == str
for f in os.listdir(dir):
fileName = dir + os.sep + f
if os.path.isdir(fileName) and os.access(fileName, os.W_OK): #if it is directory
self.process_dir(fileName) #process the elements in the directory
self.renameFile(dir, f) #rename the directory itself
else:
self.renameFile(dir, f) #if it is a file
return
if __name__=='__main__':
renamer = RenameFiles()
renamer.process_dir('.')
答案1
正如评论中所说,Python2 已被弃用。还有其他工具可以解决这个问题...
使用珀尔的rename
:
$ rename -u utf8 -n '
BEGIN{use Text::Unidecode} # 'import' needed extra module
s/.*/unidecode($&)/e; # decode utf8 -> ascii
s/\s+/_/g; # s/[[:space:]]/_/g
y/A-Z/a-z/ # translate uppercase to lower
' ./**/*.* # ** enable recursion¹
1zsh
默认情况下,bash 需要shopt -s globstar
在命令之前运行。
需要sudo apt install rename libtext-unidecode-perl
包(Debian*/Ubuntu/Mint...
)。
当输出看起来令人满意时删除-n
(又名)。dry-run
输出
rename(Linux příručka českého uživatele.pdf, linux_prirucka_ceskeho_uzivatele.pdf)
rename(LINUXTERO příkazy které se vždy hodí.pdf, linuxtero_prikazy_ktere_se_vzdy_hodi.pdf)
rename(Práce s archívy příkazové řádka.pdf, prace_s_archivy_prikazove_radka.pdf)
rename(Rekurzivní grep.txt, rekurzivni_grep.txt)
答案2
Python 2 现在是一种死亡语言(2020 年 1 月 1 日日落)
很长一段时间以来,人们编写的代码都与 python 2 和 3 兼容。所以它们很相似,但仍然存在差异。
也许最著名的是错误中提到的一个。 “print”语句现在需要括号:
打印“富”
就是现在
打印(“富”)