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python + 检查长字典中键的值

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python + 检查长字典中键的值

我们有以下 API 将结果获取到 to res，并且 res是字典类型

  res = api_req.ambari_request("/api/v1/clusters/HDP/host_components?HostRoles/component_name=NAMENODE&metrics/dfs/FSNamesystem/HAState=active")

字典res看起来像这样：

。 。

    "display_name": "NameNode",
    "init_count": 0,
    "install_failed_count": 0,
    "installed_count": 0,
    "recovery_enabled": "true",
    "repository_state": "CURRENT",
    "service_name": "HDFS",
    "started_count": 2,
    "state": "STARTED",
    "total_count": 2,
    "unknown_count": 0
},

我们需要验证字典中的所有started_count内容是否相等2

感谢为该测试找到正确的方法

答案1

python 字典值可以使用下标运算符 [] 来访问，给定一个字符串，该字符串是与您希望获取的值相对应的键。这获取与“started_count”键关联的值。


api_data = {
    "display_name": "NameNode",
    "init_count": 0,
    "install_failed_count": 0,
    "installed_count": 0,
    "recovery_enabled": "true",
    "repository_state": "CURRENT",
    "service_name": "HDFS",
    "started_count": 2,
    "state": "STARTED",
    "total_count": 2,
    "unknown_count": 0
}      

if api_data["started_count"] == 2:
    print("started_count is 2")
else:
    print("started_count is not 2")

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