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将多行以同一短语开头的行合并为一行

tag-icon • tag-icon bash shell-script sed toml
将多行以同一短语开头的行合并为一行

我正在编写一个 Bash 脚本，将 Arch Linux 包转换为我正在编写的包管理器的格式，并且我必须将一些元数据文件转换为文件格式.toml。以前，我一直在使用sed，但我只需要一些可以在 Bash 脚本中实现的东西。转换应如下所示。

输入：

... other stuff ...
depends = "some-dependency"
depends = "another-dependency"
depends = "yet-another-dependency"

输出：

... other stuff already converted ...
depends = [ "some-dependency", "another-dependency", "yet-another-dependency" ]

答案1

使用awk：

awk -F' = ' '
    $1 == "depends" {
        printf "%s %s", (flag!=1 ? "depends = [" : ","), $2
        flag=1
        next
    }
    flag {
        print " ]"
        flag=0
    }
    { print }
    END {
        if (flag) print " ]"
    }
' file

输入：

... other stuff ...
depends = "some-dependency"
depends = "another-dependency"
depends = "yet-another-dependency"
... more stuff ...
depends = "next-dependency"
depends = "and-another-dependency"

输出：

... other stuff ...
depends = [ "some-dependency", "another-dependency", "yet-another-dependency" ]
... more stuff ...
depends = [ "next-dependency", "and-another-dependency" ]

答案2

从输入文件中排除“...其他东西..”部分，您可以使用以下代码：

$ awk -F"=" 'NR==1{printf $1 " = [" } {printf $2 ","};END{print""}' infile | sed 's/.$/\]/'

depends  = [ "some-dependency", "another-dependency", "yet-another-dependency"]

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