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如何在 awk 中转义变量内的字符？

tag-icon • tag-icon bash awk scripting escape-characters
如何在 awk 中转义变量内的字符？

我正在尝试制作一个脚本，使用 awk 从 .config/okularrc 获取最近的文件名并将它们通过管道传输到 dmenu，然后返回 awk 以获取所选名称的路径。但是，我收到一个错误，告诉我在正则表达式中应该转义一个字符。
Okularrc 文件：

[Recent Files]
File1[$e]=$HOME/documents/med/oh/OH Lecture (12)_Lead Poisoning Summary.pdf
File2[$e]=$HOME/ug/Biochemistry/1. biochemistry of kidney.pdf
File3[$e]=$HOME/ug/Archives/3. UG-(mid+final)-WAREED.pdf
File4[$e]=$HOME/ug/Biochemistry/1. b)iochemistry of kidney.pdf
Name1[$e]=OH Lecture (12)_Lead Poisoning Summary.pdf
Name2[$e]=1. biochemistry of kidney.pdf
Name3[$e]=3. UG-(mid+final)-WAREED.pdf
Name4[$e]=1. b)iochemistry of kidney.pdf

我制作的脚本：

#!/bin/bash

DEBUG=1

# Get the names of the files
names=$(awk -F'=' '/^Name/{print $2} ' ~/.config/okularrc)
[ $DEBUG == 1 ] && echo -e "[*] Names are:\n$names\n"


# Pass the names to dmenu and select a file
selected_name=$(echo "$names" | dmenu -l 10 -i -p "Select a recent file:")
[ $DEBUG == 1 ] && echo -e "[*] Selected name is:\n$selected_name\n"

# Get the path of the selected file
file_path=$(awk -v name="$selected_name" -F'=' '$2 ~ name "$" && /^File/ {print $2}' ~/.config/okularrc)
[ $DEBUG == 1 ] && echo -e "[*] File path is:\n${file_path}\n"


# Run Okular with the path of the file
okular "${file_path/'$HOME'/$HOME}"

# If history is zero just start okular; TODO add browser
#[ -z $names ] && okular && exit

当我在具有“(”的文件上运行此命令时，它会给出以下输出：

[*] Names are:
1. b(iochemistry of kidney.pdf

[*] Selected name is:
1. b(iochemistry of kidney.pdf

awk: cmd. line:1: (FILENAME=/home/anonymous/.config/okularrc FNR=1) fatal: invalid regexp: Unmatched ( or \(: /1. b(iochemistry of kidney.pdf$/
[*] File path is:

我是 awk 的新手，我想了解更多信息，非常感谢您的帮助

答案1

替换了这一行：

file_path=$(awk -v name="$selected_name" -F'=' '$2 ~ name "$" && /^File/ {print $2}' ~/.config/okularrc)

用这一行：

file_path=$(awk -v name="$selected_name" -F'=' 'index($2,name) && /^File/ {print $2}' ~/.config/okularrc)

致谢@steeldriver

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