号码显示出来,但脚注文本缺失。如何解决?
\documentclass{article}
\usepackage{algorithm}
% Need it for floating environment
\usepackage[noend]{algpseudocode}
% Hide endif .etc
\usepackage{caption}
% Need it for \caption*
\usepackage{xspace}
% Fix macro spacing bug
\algrenewcommand{\algorithmicrequire}{\textbf{Input:}}
\algrenewcommand{\algorithmicensure}{\textbf{Output:}}
\algrenewcommand{\algorithmicforall}{\textbf{for each}}
% \algrenewcommand instead of \renewcommand according to manual
\newcommand{\To}{\textbf{to}\xspace}
% Not stated in manual, \Return and \algorithmicreturn are defined, but no \algorithmicstate, why?
\newcommand{\Dosth}{\State \textbf{Do Something}\xspace}
% Note no space before \xspace
\newcommand{\Please}[1]{\State \textbf{#1}}
\newcommand{\ForEach}{\ForAll}
% Fail to use \algorithmicforall, why?
\begin{document}
\begin{algorithm}
\caption*{\textbf{Algorithm:} \textsc{Depth First Search}} \label{alg:dfs1}
\begin{algorithmic}[1]
\Function{DFS}{$v$}
\State $count \gets count + 1$
\Please{mark} $v$ with $count$
\Dosth with $v$
\ForEach{vertex $w \in \mathcal{V}$ adjacent to $v$}
\If{$w$ is marked with $0$} \Comment Only needed to exclude its parent.\footnote{No sibling is visited before the loop. Each sibling will be visited exactly once due to the nature of the loop.}
\State \Call{DFS}{$w$}
\EndIf
\EndFor
\State \Return
\EndFunction
\end{algorithmic}
\end{algorithm}
\end{document}
答案1
而不是命令\footnote
,您可以\footnotemark
使用\footnotetext
:
\documentclass{article}
\usepackage{algorithm}
% Need it for floating environment
\usepackage[noend]{algpseudocode}
% Hide endif .etc
\usepackage{caption}
% Need it for \caption*
\usepackage{xspace}
% Fix macro spacing bug
\algrenewcommand{\algorithmicrequire}{\textbf{Input:}}
\algrenewcommand{\algorithmicensure}{\textbf{Output:}}
\algrenewcommand{\algorithmicforall}{\textbf{for each}}
% \algrenewcommand instead of \renewcommand according to manual
\newcommand{\To}{\textbf{to}\xspace}
% Not stated in manual, \Return and \algorithmicreturn are defined, but no \algorithmicstate, why?
\newcommand{\Dosth}{\State \textbf{Do Something}\xspace}
% Note no space before \xspace
\newcommand{\Please}[1]{\State \textbf{#1}}
\newcommand{\ForEach}{\ForAll}
% Fail to use \algorithmicforall, why?
\begin{document}
\begin{algorithm}
\caption*{\textbf{Algorithm:} \textsc{Depth First Search}} \label{alg:dfs1}
\begin{algorithmic}[1]
\Function{DFS}{$v$}
\State $count \gets count + 1$
\Please{mark} $v$ with $count$
\Dosth with $v$
\ForEach{vertex $w \in \mathcal{V}$ adjacent to $v$}
\If{$w$ is marked with $0$} \Comment Only needed to exclude its parent.\footnotemark
\State \Call{DFS}{$w$}
\EndIf
\EndFor
\State \Return
\EndFunction
\end{algorithmic}
\end{algorithm}
\footnotetext{No sibling is visited before the loop. Each sibling will be visited exactly once due to the nature of the loop.}
\end{document}
答案2
我建议尝试将它们添加到序言中:
\usepackage{footnote}
\makesavenoteenv{algorithm}
在某些情况下,它确实有效,但我发现它们可能并不总是有效,因为从 latex.org 上查看