![仅打印两个符号之间的文本](https://linux22.com/image/247191/%E4%BB%85%E6%89%93%E5%8D%B0%E4%B8%A4%E4%B8%AA%E7%AC%A6%E5%8F%B7%E4%B9%8B%E9%97%B4%E7%9A%84%E6%96%87%E6%9C%AC.png)
我有一个包含一些文本的宏:
\textmacro{This is some text.}
正常情况下,编译时应该只打印文本,如下所示:
This is some text.
有时,文本中也会包含“①”和“②”,比如:
\textmacro{① This is some text. ② This is some other text.}
当发生这种情况时,我需要它仅打印出现在“①”和“②”之间的文本,如下所示:
This is some text.
如果出现“①”和“②”符号,如何让宏打印出它们之间的文本#1
,否则只打印所有文本?
答案1
你想要一个 ConTeXt 答案,对吧?每当我发现自己想“我知道如何用普通的编程语言做到这一点”时,我就会将我想要操作的文本转移到 LuaTeX 中。来自 wiki 的模板:
% First, the Lua function that will process the string
\startluacode
-- remember, using the userdata namespace prevents conflicts
userdata = userdata or {}
function userdata.printBetweenMarks(str, m1, m2)
-- default delimiters
m1 = m1 or '①'
m2 = m2 or '②'
match_pattern = string.format('%s(.*)%s', m1, m2)
str = string.match(str, match_pattern) or str
context(str)
end
\stopluacode
% Secondly, the ConTeXt command that passes the string to the Lua function.
\def\textmacro#1%
{\ctxlua{userdata.printBetweenMarks([===[#1]===])}}
% Note that Lua sees the text as-is, so we have to wrap it in string
% delimiters ourselves.
% [=*[ is Lua's double-bracket string delimiter style; this way, the
% code only fails if the text contains ']===]'.
编辑:删除了print()
我用于调试的语句
答案2
\documentclass{article}
\makeatletter
\def\textmacro#1{\expandafter\@textmacro#1①②\@nil}
\def\@textmacro#1①#2②#3\@nil{%
\ifx\relax#2\relax#1\else#2\fi}
\makeatother
\begin{document}
\textmacro{This is some text.}\par
\textmacro{① This is some text. ② This is some other text.}\par
\textmacro{This is some text ① This is some other text. ② This is some text.}
\end{document}