![Tikz:在圆圈内绘制锯齿线](https://linux22.com/image/249589/Tikz%EF%BC%9A%E5%9C%A8%E5%9C%86%E5%9C%88%E5%86%85%E7%BB%98%E5%88%B6%E9%94%AF%E9%BD%BF%E7%BA%BF.png)
我需要在不使用装饰的情况下在圆圈内绘制一条锯齿线。线条的大小和位置应与圆圈的大小相关。我使用了以下代码:
\documentclass{standalone}
\usepackage{tikz}
\usetikzlibrary{calc}
\begin{document}
\begin{tikzpicture}
\node[draw,circle,minimum size=1cm] (C) at (0,0){};
\draw ($($ (C.west)!.1!(C.east) $)-(0,30pt)$) --($ (C.west)!.1!(C.east) $)
--($ (C.west)!.25!(C.east) $) --($($ (C.west)!.3!(C.east) $)+(0,3pt)$)
--($($ (C.west)!.4!(C.east) $)-(0,3pt)$) --($($ (C.west)!.5!(C.east) $)+(0,3pt)$)
--($($ (C.west)!.6!(C.east) $)-(0,3pt)$) --($($ (C.west)!.7!(C.east) $)+(0,3pt)$)
--($ (C.west)!.75!(C.east) $) --($ (C.west)!.9!(C.east) $)
--($($ (C.west)!.9!(C.east) $)-(0,30pt)$);
\end{tikzpicture}
\end{document}
得到这个:
问题是,如果我想调整圆圈的大小,垂直线会变得太短(或太长),我必须手动修复“垂直坐标”。
可以锚定相对于节点形状的垂直坐标吗?
答案1
除了将“腿”定义为(0,-30pt)
(当然,它不能缩放)之外,您还可以使用($(C.north)-(C.south)$)
:
\documentclass{standalone}
\usepackage{tikz}
\usetikzlibrary{calc}
\begin{document}
\begin{tikzpicture}
\node[draw,circle,minimum size=1.2cm] (C) at (0,0){};
\draw ($($ (C.west)!.1!(C.east) $)-($(C.north)-(C.south)$)$)--($ (C.west)!.1!(C.east) $)
--($ (C.west)!.25!(C.east) $)--($($ (C.west)!.3!(C.east) $)+(0,3pt)$)
--($($ (C.west)!.4!(C.east) $)-(0,3pt)$)--($($ (C.west)!.5!(C.east) $)+(0,3pt)$)
--($($ (C.west)!.6!(C.east) $)-(0,3pt)$)--($($ (C.west)!.7!(C.east) $)+(0,3pt)$)
--($ (C.west)!.75!(C.east) $)--($ (C.west)!.9!(C.east) $)
--($($ (C.west)!.9!(C.east) $)-($(C.north)-(C.south)$)$);
\end{tikzpicture}
\begin{tikzpicture}
\node[draw,circle,minimum size=1.8cm] (C) at (0,0){};
\draw ($($ (C.west)!.1!(C.east) $)-($(C.north)-(C.south)$)$)--($ (C.west)!.1!(C.east) $)
--($ (C.west)!.25!(C.east) $)--($($ (C.west)!.3!(C.east) $)+(0,3pt)$)
--($($ (C.west)!.4!(C.east) $)-(0,3pt)$)--($($ (C.west)!.5!(C.east) $)+(0,3pt)$)
--($($ (C.west)!.6!(C.east) $)-(0,3pt)$)--($($ (C.west)!.7!(C.east) $)+(0,3pt)$)
--($ (C.west)!.75!(C.east) $)--($ (C.west)!.9!(C.east) $)
--($($ (C.west)!.9!(C.east) $)-($(C.north)-(C.south)$)$);
\end{tikzpicture}
\end{document}