使列表尊重基线延伸

Question

在特定情况下，我必须使用lstlisting而不是Verbatim，因为数学转义无法与后者正常工作。我设法让两者看起来一样，但lstlisting忽略了我的baselinestretch设置，因此行距太大：

\documentclass{article}
\usepackage[T1]{fontenc}
\usepackage{fancyvrb}
\usepackage{listings}
\usepackage[scaled=.73]{beramono}
\fvset{baselinestretch=0.94}
\lstdefinelanguage{scala}{
  morekeywords={type}%
}
\lstset{
  language=scala,%
% baselinestretch=0.94,% keyword doesn't exist
  basicstyle=\ttfamily,%
  fancyvrb=true,%
  mathescape=true,%
}

\begin{document}

\begin{lstlisting}
type Vertex = ($\mathit{lb}_\mathsf{pre}$: Label, $\mathit{lb}_\mathsf{post}$: Label)
Next Line
Next Line
\end{lstlisting}

\begin{Verbatim}
type Vertex = ($\mathit{lb}_\mathsf{pre}$: Label, $\mathit{lb}_\mathsf{post}$: Label)
Next Line
Next Line
\end{Verbatim}

\end{document}

您可以在此处看到不同的行距：

差异不是很大，但对长列表的影响很大。将基线拉伸应用于 的最佳方法是什么lstlisting？

Answer 1

使用basicstyle=\linespread{0.94}\ttfamily

如下例所示，各行间距完全相同

\documentclass{article}
\usepackage[T1]{fontenc}
\usepackage{fancyvrb}
\usepackage{listings}
\usepackage[scaled=.73]{beramono}
\fvset{baselinestretch=.94}
\lstdefinelanguage{scala}{
  morekeywords={type}
}
\lstset{
  language=scala,
  basicstyle=\linespread{.94}\ttfamily,
  fancyvrb=true,
  mathescape=true,
}

\begin{document}

\begin{lstlisting}
type Vertex = ($\mathit{lb}_\mathsf{pre}$: Label, $\mathit{lb}_\mathsf{post}$: Label)
Next Line
Next Line
\end{lstlisting}

\kern-50pt % back up to see that the lines are equally spaced

\begin{Verbatim}
type Vertex = ($\mathit{lb}_\mathsf{pre}$: Label, $\mathit{lb}_\mathsf{post}$: Label)
Next Line
Next Line
\end{Verbatim}

\end{document}