使用 Tikzpicture,我有以下自动机:
\documentclass{article}
\usepackage{tikz}
\begin{document}
\usetikzlibrary{positioning,arrows,automata}
\begin{center}
\begin{tikzpicture}[>=stealth',shorten >=1pt,node distance=2cm,on grid,initial/.style={}]
\node[state,initial] (a0) {};
\node[state] (a1) [right =of a0] {};
\node[state] (a2) [right =of a1] {};
\node[state] (a3) [above =of a2] {};
\node[state] (a4) [below =of a0] {};
\node[state] (a6) [right =of a4] {};
\node[state] (a7) [right =of a2] {};
\node[state] (a8) [right =of a7] {};
\node[state] (a9) [right =of a8] {};
\node[state] (a5) [above =of a9] {};
\node[state] (b0) [right =of a6] {};
\node[state] (b1) [right =of b0] {};
\node[state] (b2) [right =of b1] {};
\node[state] (b3) [right =of b2] {};
\node[state] (b4) [right =of a9] {};
\tikzset{every node/.style={fill=white}}
\tikzset{mystyle/.style={->,double=red}}
\path (a4) edge [mystyle] node {$0$} (a6)
(a2) edge [mystyle] node {$0$} (a7)
(b0) edge [mystyle] node {$0$} (b1);
\tikzset{mystyle/.style={->,double=blue}}
\path (a3) edge [mystyle] node {$1$} (a5)
(a8) edge [mystyle] node {$1$} (a9)
(b2) edge [mystyle] node {$1$} (b3);
\tikzset{mystyle/.style={->,double=yellow}}
\path (a0) edge [mystyle] node {$\varepsilon$} (a1)
(a1) edge [mystyle] node {$\varepsilon$} (a2)
(a1) edge [mystyle] node {$\varepsilon$} (a3)
(a1) edge [mystyle] node {$\varepsilon$} (a4)
(a6) edge [mystyle] node {$\varepsilon$} (b0)
(a7) edge [mystyle] node {$\varepsilon$} (a8)
(b1) edge [mystyle] node {$\varepsilon$} (b2)
(a9) edge [mystyle] node {$\varepsilon$} (b4)
(a5) edge [mystyle] node {$\varepsilon$} (b4)
(b3) edge [mystyle] node {$\varepsilon$} (b4);
\end{tikzpicture}
\end{center}
\end{document}
现在,我想添加一个黄色的 epsilon 箭头,从最左边的节点 (a0) 到最右边的节点 (b4)。但是,我完全不知道如何做到这一点,而不让箭头穿过自动机的其余部分。我可以在这里得到一些帮助吗?
答案1
您可以使用[bend left]
评论中所建议的选项,并赋予它一个角度,例如[bend left=70]
,然后曲线将以该角度离开起点和终点节点,因此生成的路径是对称的。
(a0) edge[mystyle, bend left=70] node {$\varepsilon$} (b4);
然而,在这种特殊情况下,由于图形不对称,这种生成路径的方式看起来有点丑陋(恕我直言):
通过选项in
,out
您可以为路径的结尾指定不同的角度,从而创建与图形其余部分更相配的不对称弧:
(a0) edge[mystyle, out=50,in=90] node {$\varepsilon$} (b4);