谁能告诉我如何绘制一个周围有黑色边框的矩形?
我希望以下 TikZ 图片中的所有矩形都具有此效果:
\documentclass[tikz]{standalone}
\begin{document}
\begin{tikzpicture}[every node/.style = {shape = rectangle,
rounded corners,
fill = black!30!white,
minimum width = 3cm,
minimum height = 1.5cm,
align = center,
text = black},
black edge/.style = { -,
ultra thick,
black,
shorten >= 2pt}]
% the nodes : possible \newcommand*\dx{5} \newcommand*\dy{2}
\node(0;0) at (5,0) {Patients};
\node(1;1) at (10, 2) {Treatment $A_1$};
\node(1;-1) at (10,-2) {Treatment $A_2$};
\foreach \j in {-1,1}
{ \draw[black edge] (0;0.east) -- (1;\j.west); }
\end{tikzpicture}
\end{document}
答案1
您可以使用draw,double=<color>,double distance = <dimen>
以下every node
风格:
\documentclass{article}
\setlength{\parindent}{0mm}
\usepackage{paralist}
\usepackage{tikz}
\begin{document}
\begin{tikzpicture}[every node/.style = {shape = rectangle,
rounded corners,
draw, %% here
double=red, %% here
double distance =1pt, %% here
fill = black!30!white,
minimum width = 3cm,
minimum height = 1.5cm,
align = center,
text = black},
black edge/.style = { -,
ultra thick,
black,
shorten >= 2pt}]
% the nodes : possible \newcommand*\dx{5} \newcommand*\dy{2}
\node(0;0) at (5,0) {Patients};
\node(1;1) at (10, 2) {Treatment $A_1$};
\node(1;-1) at (10,-2) {Treatment $A_2$};
\foreach \j in {-1,1}
{ \draw[black edge] (0;0.east) -- (1;\j.west); }
\end{tikzpicture}
\end{document}
如果您不想要颜色,请使用简单double
代替double=<color>
。
答案2
使用 PSTricks。
\documentclass[pstricks,border=12pt]{standalone}
\newpsobject{myrec}{psframe}
{
border=2\pslinewidth,
bordercolor=black,
}
\begin{document}
\begin{pspicture}[showgrid](4,3)
\myrec[linecolor=yellow](2,1.5)
\myrec[linecolor=white](2.5,2)(4,3)
\end{pspicture}
\end{document}