如何在 tikz 中将箭头放在圆圈内？

Question

我需要您的帮助才能在 tikz 中创建下图。我是 tikz 的初学者。

我在以下页面中看到了示例，但我需要如图所示的方式，而我无法制作 TikZ：使用循环绘制节点网格

Answer 1

也许这个代码可以帮到你。我们无法应用你链接中的代码，因为我们不知道箭头的位置是否是自动的。很大一部分需要手动绘制。下一个代码不是很优雅，但你可以尝试做得更好。一个好主意是在绘制网格之前用一个循环确定所有节点的坐标，就像在链接中一样，没有定义节点（只有坐标）。

\documentclass{article}
\usepackage{tikz}

\begin{document}
\begin{tikzpicture}[
    down/.style={path picture={
     \draw[->]  ([yshift=-3pt]path picture bounding box.north)  
             -- ([yshift=3pt]path picture bounding box.south);}},
    up/.style={path picture={
      \draw[->]  ([yshift=3pt]path picture bounding box.south)  
              -- ([yshift=-3pt]path picture bounding box.north);}},
    every node/.style={circle,draw, minimum size=1 cm}]

    \node[label=45:$1$,up]   (n-1-1)          {};
    \node[label=45:$2$,down] (n-1-2) at (2,0) {};
    \node[label=45:$3$,up]   (n-1-3) at (4,0) {};
    \node[label=45:$n$,up]   (n-1-4) at (6,0) {};

    \node[label=45:$n+1$,down] (n-2-1)  at (0,-2) {};
    \node[label=45:$n+2$,up]   (n-2-2)  at (2,-2) {};
    \node[label=45:$n+3$,down] (n-2-3)  at (4,-2) {};
    \node[label=45:$n+4$,up]   (n-2-4)  at (6,-2) {};

    \node[up]   (n-3-1)  at (0,-4)  {};
    \node[up]   (n-3-2)  at (2,-4)  {};
    \node[down] (n-3-3)  at (4,-4)  {};
    \node[down] (n-3-4)  at (6,-4)  {};

    \node[up]   (n-4-1)  at (0,-6) {};
    \node[down] (n-4-2)  at (2,-6) {};
    \node[up]   (n-4-3)  at (4,-6) {};
    \node[down] (n-4-4)  at (6,-6) {};  

    \foreach \i [count=\xi from 2] in {1,...,2}
        \foreach \j [count=\xj from 2] in {1,...,3}
           \draw (n-\i-\j) -- (n-\xi-\j);

     \foreach \j [count=\xj from 2] in {1,...,4}
           \draw[thick,dotted] (n-3-\j) -- (n-4-\j);


    \foreach \i [count=\xi from 2] in {1,...,3}
        \foreach \j [count=\xj from 2] in {1,...,2}
             \draw (n-\i-\j) -- (n-\i-\xj);

   \foreach \i [count=\xi from 2] in {1,...,4}
            \draw[thick,dotted]  (n-\i-3) -- (n-\i-4);

\draw (n-4-1) -- (n-4-2) (n-4-2)--(n-4-3) ;
\draw (n-1-4) -- (n-2-4) (n-2-4)--(n-3-4) ;
\foreach \i in {1,...,4} {%
     \draw (n-\i-4)--++(1.5,0) ;
     \draw (n-4-\i)--++(0,-1.5) ;
     }
\end{tikzpicture}

\end{document}

做一些可能更好的事情。我删除了很大一部分代码。你现在的问题是绘制圆内的顶点和箭头。如果你想设计一些节点，我写了所有的标签来帮助你

\documentclass{minimal}
\usepackage{tikz}

\begin{document}
\begin{tikzpicture}[darkstyle/.style={circle,draw,minimum size=10mm}]
  \foreach \x in {0,...,4}
    \foreach \y in {0,...,4} 
       {%\pgfmathtruncatemacro{\label}{\x - 5 *  \y +21}
       \node [darkstyle,label=45:$n-\x-\y)$]  (n-\x-\y) at (2*\x,2*\y) {};} 

  % \foreach \x in {0,...,4}
  %   \foreach \y [count=\yi] in {0,...,3}  
  %     \draw (n-\x-\y)--(n-\x-\yi) (n-\y-\x)--(n-\yi-\x) ;

\end{tikzpicture}
\end{document}