如何使此节点中的 \vdots 垂直居中？

Question

我希望\vdots此链中的 到两个箭头的距离相同。我知道我可以手动移动节点以使其看起来正确，但一定有更好的解决方案。怎么做？

\documentclass{standalone}
\usepackage{tikz}
\usetikzlibrary{chains}
\begin{document}
\begin{tikzpicture}[start chain=going below,every join/.style={->}]
    \node [on chain, join] {A};
    \node [on chain, join] {$\vdots$};
    \node [on chain, join] {B};
\end{tikzpicture}
\end{document}

Answer 1

\vdots是为矩阵设计的。您可以使用不在顶部添加空间的修改版本：

\documentclass{standalone}
\usepackage{tikz}
\usetikzlibrary{chains}

\makeatletter
\DeclareRobustCommand{\rvdots}{%
  \vbox{
    \baselineskip4\p@\lineskiplimit\z@
    \kern-\p@
    \hbox{.}\hbox{.}\hbox{.}
  }}
\makeatother


\begin{document}
\begin{tikzpicture}[start chain=going below,every join/.style={->}]
    \node [on chain, join] {A};
    \node [on chain, join] {\rvdots};
    \node [on chain, join] {B};
\end{tikzpicture}
\end{document}

Answer 2

尝试旋转\cdots。

\documentclass{standalone}
\usepackage{tikz}
\usetikzlibrary{chains}
\begin{document}
\begin{tikzpicture}[start chain=going below,every join/.style={->}]
    \node [on chain, join] {A};
    \node [on chain, join] {\rotatebox{90}{$\cdots$}};
    \node [on chain, join] {B};
\end{tikzpicture}
\end{document}