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$\quad$在不同的线路上效果不一样吗？

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$\quad$在不同的线路上效果不一样吗？ 
%% AMS-LaTeX Created by Wolfram Mathematica 9.0 : www.wolfram.com

\documentclass{article}
\usepackage{amsmath, amssymb, graphics, setspace}

\newcommand{\mathsym}[1]{{}}
\newcommand{\unicode}[1]{{}}

\begin{document}

\section*{ORDERED SETS }

\subsection*{1.5 Definition}

$\quad $Let \(S\) be a set. An order on \(S\) is a relation, denoted by \(<\), with the following two properties: \\
(i) If \(x\in S\) and \(y\in S\) then one and only one of the statements

\[x<y, x=y, y<x\]

is true. \\
(ii) If \(x, y, z \in S\), if \(x < y\) and \(y < z\), then \(x < z\).

$\quad $The statement $\texttt{"}$\(x < y\) may be read as \(x\) is less than \(y\) or \(x\) is smaller than \(y\) or \(x\) precedes \(y\)$\texttt{"}$.


$\quad $It is often convenient to write \(y > x\) in place of \(x < y\).

$\quad $The notation \(x < y\) indicates that \(x < y\) or \(x = y\), without specifying which of these two is to hold. In other words, \(x < y\)
is the negation of \(x > y\).



\end{document}

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答案1

$\quad$和之类的 hack$\texttt{"}$都是错误的。\\在普通文本中也应该是例外，而不是结束一行的常用方法。

如果希望标题后缩进，请加载indentfirst包。不要“手工制作”枚举列表，而是使用enumerate（也许可以用 来增强它enumitem）。

\documentclass{article}
\usepackage{amsmath, amssymb, enumitem, indentfirst}

\newcommand{\mathsym}[1]{{}}
\newcommand{\unicode}[1]{{}}

\begin{document}

\section*{ORDERED SETS}

\subsection*{1.5 Definition}

Let \(S\) be a set. An order on \(S\) is a relation, denoted by \(<\), with the 
following two properties:
\begin{enumerate}[leftmargin=*,label=(\roman*)]
\item If \(x\in S\) and \(y\in S\) then one and only one of the statements
\[
x<y,\quad x=y,\quad y<x
\]
is true.
\item If \(x, y, z \in S\), if \(x < y\) and \(y < z\), then \(x < z\).
\end{enumerate}
The statement ``\(x < y\)'' may be read as \(x\) is less than \(y\) or \(x\) is 
smaller than \(y\) or \(x\) precedes \(y\).

It is often convenient to write \(y > x\) in place of \(x < y\).

The notation \(x < y\) indicates that \(x < y\) or \(x = y\), without specifying 
which of these two is to hold. In other words, \(x < y\) is the negation of \(x > y\).

\end{document}

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答案2

也许您应该尝试另一种方法来优化代码和输出。

所有这些加在一起可能会给你带来类似的东西。

\documentclass[11pt]{article}
\usepackage[T1]{fontenc}
\usepackage{mathtools}
\usepackage{amssymb,amsthm}
\usepackage{enumitem}

\swapnumbers
\theoremstyle{definition}
\newtheorem{definition}{Definition}[section]

\begin{document}
  \section{Ordered Sets}
    \begin{definition}
      Let \(S\) be a set. An order on \(S\) is a relation, denoted by \(<\), with the following two properties:
      \begin{enumerate}[label={(\roman*)}]
        \item If \(x\in S\) and \(y\in S\) then one and only one of the statements
          \[
            x<y,\quad x=y,\quad y<x
          \]
        is true.
        \item If \(x, y, z \in S\), if \(x < y\) and \(y < z\), then \(x < z\).

          The statement "\(x < y\) may be read as \(x\) is less than \(y\) or \(x\) is smaller than \(y\) or \(x\) precedes \(y\)".

          It is often convenient to write \(y > x\) in place of \(x < y\).

          The notation \(x < y\) indicates that \(x < y\) or \(x = y\), without specifying which of these two is to hold. In other words, \(x < y\) is the negation of \(x > y\).
      \end{enumerate}
    \end{definition}
\end{document}

进一步的定制取决于您。

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